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ZanzabumX [31]
3 years ago
14

Refer to Figure 13-2 and determine how much parent material will be left after five half-lives

Physics
2 answers:
Kamila [148]3 years ago
4 0

Answer: 3.125g

Explanation: This is a type of radioactive decay and all the radioactive process follow first order kinetics.

Half life is the time required to decompose half of the reactants. thus after every half life the reactant will decompose to half of its present value.

Now, to calculate the number of half lives, we use the formula:

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = ?

a_o =Let Initial amount of the reactant = 100 g

n = number of half lives

a=\frac{100}{2^5}

a=3.125g

Tomtit [17]3 years ago
4 0
After five half-lives, there will be

           (1/2) · (1/2) · (1/2) · (1/2) · (1/2)  =  1/32  =  3.125%

of the original material remaining.
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A high voltage transmission line with a resistance of 0.51 Ω/km carries a current of 1099 A. The line is at a potential of 1300
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<h2>Answer:</h2>

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<h2>Explanation:</h2>

First of all, we need to figure out what is the resistance in that line. In this problem, the total resistance is not given directly, but we can calculate it because we know it in terms of 0.51 Ω/km and since the distance from the power station to the city is 156km, then:

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P=I^2R \\ \\ Where: \\ \\I=1099A \\ \\ P=(1099)^2(79.56) \\ \\ P=96092647.56W \\ \\ Remember \ that \ 1MW=10^6W \ So: \\ \\ P=96092647.56W(\frac{1M}{10^6}) \\ \\ \boxed{P=96.09MW}

Finally, the power loss due to resistance in the line is 96.09MW

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3 years ago
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