Which of the following statements is TRUE concerning forces?

A small car has a head-on collision with a large truck. Which of the following statements concerning the magnitude of the averag

Veronika [31]

Answer:

The small car and the truck experience the same average force.

Explanation:

The average net force will be the resultant force of the average forces of both vehicles. On collision, they'll both experience the same impact force, but the deceleration and deformation felt by the individual vehicle will be proportional to the mass of the vehicle. This is why it will seem like the car will have more force but is not actually so.

4 0

3 years ago

The weight of an object on a planet depends not only on its mass, but also on its distance from the planets center. Uranus has m

Ierofanga [76]

The further an object is from the centre of a planet, the lower it's gravitational force. Uranus had 14 times as much mass as earth, but it's also a lot bigger than earth. So assuming an object is on the surface of Uranus, it would be really far away from the centre of Uranus, therefore the gravitational force is less.

Hope this helps!

5 0

3 years ago

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Which of the following would be the best name for MgCl2?

Juliette [100K]

MgCl2 is magnesium chloride.
Hope this helps!

8 0

4 years ago

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An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N

algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

4 0

3 years ago

Earth has a mass of 5.97 × 1024 kg and a radius of 6.38 × 106 m, while Saturn has a mass of 5.68 × 1026 kg and a radius of 6.03

hammer [34]

Answer: mass on earth = 625.792 N, mass on saturn = 666.75 N

Explanation: weight of an object = mg

Where g = acceleration due to gravity =GM/r²

Where G = gravitational constant, M = mass of planet and r = radius of planet.

Let us start with earth.

G =gravitational constant of the earth =6.67×10^-11 m³ /kgs²

Me = mass of earth = 5.97×10^24 kg

re = radius of earth = 6.38×10^6 m

Acceleration due to gravity on earth = (6.67×10^-11×5.97×10^24) /(6.38×10^6)²

Acceleration due to gravity on earth = 3.98×10^14 /4.07×10^13

Acceleration due gravity on earth = 9.778 m/s²

The mass of the person is 64 kg, hence his weight on earth is given as

W = mass × Acceleration due gravity on earth = 64 ×9.778 = 625.792 N

For saturn.

G =gravitational constant of the earth =6.67×10^-11 m³ /kgs²

Ms = mass of saturn = 5.68×10^26kg

rs= radius of saturn= 6.03×10^7 m

Acceleration due to gravity on saturn= (6.67×10^-11×5.68×10^26 /(6.03×10^7)²

Acceleration due to gravity on saturn= 3.788×10^16/3.636×10^15

Acceleration due gravity on saturn= 10.417 m/s²

The mass of the person is 64 kg, hence his weight on saturn is given as

W = mass × Acceleration due gravity on saturn = 64 ×10.417 = 666.75 N

3 0

3 years ago