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luda_lava [24]
3 years ago
11

What is the value of (6-2) with the exponet 3? write your anewer as a whole number.

Mathematics
1 answer:
frozen [14]3 years ago
4 0
64 6-2=4 then 4 times 4= 16 times 4 equals 64
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( expressions)<br> A plant grew 2 cm every day for d days. How much did it grow?
navik [9.2K]
Trick question it grew exactly 2 cm  since we don't know the value of  d there can't be an outcome

6 0
3 years ago
Read 2 more answers
If g(x) = 4x + 1 and g(x) = -11, find x.
podryga [215]

Answer:

x = - 3

Step-by-step explanation:

g(x) = 4x + 1...... (1)

g(x) = -11.... (2)

From equations (1) & (2)

-11 = 4x + 1

-11 - 1 = 4x

-12 = 4x

-12/4 = x

-3 = x

x = - 3

3 0
3 years ago
Line segments JK and JL in the xy-coordinate plane both have a common endpoint J (-4,11) and midpoints an M1 (2,16) and M2 (-3,5
Arisa [49]

Answer:

12.1  

Step-by-step explanation:

The dashed line joining M₁ and M₂ is the hypotenuse of a right triangle as shown in red below.

The base of the triangle is

x₂ - x₁ = 2 - (-3) = 2+ 3 = 5

The height of the triangle is

y₂ - y₁ = 16 - 5 = 11

We can now use Pythagoras' theorem to calculate distance between the two midpoints.

x² = 5² + 11² = 25 + 121 = 146

x = √146 = 12.1

The distance between M₁ and M₂ is 12.1.

8 0
3 years ago
A certain bay with very high tides displays the following behavior. In one 12-h period the water starts at mean sea level, rises
Firdavs [7]

Answer:

the required equation is; y = 21 sin(πt/6)

Step-by-step explanation:

Given the data in the question;

Water rises above sea level = 21 ft

Water drops below sea level = 21 ft

so

maximum = 21 ft and also

minimum = 21 ft

Amplitude = ( maximum + minimum ) / 2

Amplitude = ( 21 + 21 ) / 2

Amplitude = ( 21 + 21 ) / 2 = 42/2 = 21 ft

Period = 12 hours

and we know that; period = 2π/b

so

12 = 2π/b

12b = 2π

b = 2π / 12

b = π/6

Standard equation for simple harmonic is; y = asin(bt)

we substitute

y = 21 sin(πt/6)

Hence the required equation is; y = 21 sin(πt/6)

7 0
3 years ago
Hope you all have a great day!
ArbitrLikvidat [17]

u tooooooo!!

ʕ•ᴥ•ʔ

ʕ⁀㉨⁀ʔ

(๏㉨๏)

ʕ≧ᴥ≦ʔ

4 0
3 years ago
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