Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
Answer: Average or Mean
Step-by-step explanation:
The center of measure calculated was the average or mean. To get the mean of a set of numbers, we have to add all the numbers given and then divide them by the numbers.
In this case, the mean of 3,7,11,11,16 will be:
= (3 + 7 + 11 + 11 + 16) / 5
= 48/5
= 9.6
Answer:
x=3
Step-by-step explanation:
First would need to convert the radical into a number.
And since if you have a perfect square of a radical it goes outside the square root sign, you would take the 3 and square it to make 9 and then take the 2 inside the square root sign and multiply so you have the square root of 18|
Since we have 
as the Leg c we would need to square it, squaring a square root sign would just cause them to be cancelled out and you being left with 18, afterwards find the square of 3, which is 9
18-9=9
square root of 9 = 3
I dont know what you mean but i devided 17 and 1569 and it =s 0.0108349267
