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vagabundo [1.1K]
3 years ago
6

If the bases of an isosceles trapezoid have lengths of 13 and 26 what is the length of the median

Mathematics
2 answers:
alukav5142 [94]3 years ago
6 0

Answer: the answer is C . 19.5 units - APEX :D

Reika [66]3 years ago
5 0

Answer:

Answer is 19.5 units

Step-by-step explanation:

Given that there is a trapezoid.

Its bases are 13 and 26 respectively.

Non parallel sides are congruent

To find the median that is the length of line connecting the midpoints of the non parallel sides

If we draw any one diagonal we see that median is the line connecting the mid point of two triangles with the parallel sides as bases

Hence length of median= 1/2 (base 1+base 2)

(By triangle mid point theorem)

= 1/2 (13+26)

=19.5 units

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A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of
Gwar [14]

\bold{\huge{\underline{ Solution}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • A marker in the center of the fairway is 150 yards away from the centre of the green
  • While standing on the marker and facing the green, the golfer turns 100° towards his ball
  • Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

  • Distance between marker and centre of green is 150 yards
  • <u>That </u><u>is</u><u>, </u>Height = 150 yards
  • For facing the green , The golfer turns 100° towards his ball
  • <u>That </u><u>is</u><u>, </u>Angle = 100°
  • The golfer peces off 30 yards to his ball
  • <u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}

  • Here, a = perpendicular height
  • b = base
  • c = hypotenuse
  • cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}

\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}

\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}

\sf{ x^{2} = 22500 + 900 + 156.6}

\sf{ x^{2} = 23556.6}

\bold{ x = 153.48\: yards }

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

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The triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

The given coordinates are X(6,1) Y(-2,-3) Z(0,3).

<h3>What are coordinates?</h3>

A coordinate system is a system in geometry that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold, such as Euclidean space, in a unique way.

We know that, Distance formula =\sqrt{(x_{2}-x_{1}  )^{2}+(y_{2}-y_{1}  )^{2}  }

Now, XY=\sqrt{(-2-6)^{2}+(-3-1)^{2}  }=\sqrt{80} units

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Here, YZ=XZ

Hence, the triangle with the given coordinates X(6,1) Y(-2,-3) Z(0,3) is an isosceles triangle.

To know more about the coordinate geometry visit:

brainly.com/question/20393391

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