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IgorC [24]
3 years ago
11

Select the values that make the inequality h < 1 true.

Mathematics
1 answer:
kari74 [83]3 years ago
4 0
H = 0 and all negative numbers
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Let f(x)=16x^2-x. Find f(x+1)-f(x)
olasank [31]

f(x+1) = 16(x+1)² - (x+1) = 16(x²+2x+1) - x - 1

= 16x² + 32x + 16 - x - 1 = 16x²+31x+15

so

f(x+1)-f(x) = 16x²+31x+15 - (16x² - x)

= 16x²+31x+15 - 16x² + x

= 32x + 15

8 0
3 years ago
Please help, multiple choice
tensa zangetsu [6.8K]

Answer:

A. 13

Step-by-step explanation:

Pythagorean Theorem: a^2+ b^2=c^2

a = 12

b = 5

c = ?

12^2+5^2=c^2

144 + 25 = c^2

169 = c^2

c = sqrt(169)

c = 13

4 0
4 years ago
Read 2 more answers
Please give a step-by-step solution of 2x^2 +12x = 6 (by completing the square)
sp2606 [1]

Answer:

x = - 3 ± 2\sqrt{3}

Step-by-step explanation:

Given

2x² + 12x = 6 ( divide through by 2 )

x² + 6x = 3

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(3)x + 9 = 3 + 9

(x + 3)² = 12 ( take the square root of both sides )

x + 3 = ± \sqrt{12} = ± 2\sqrt{3} ( subtract 3 from both sides )

x = - 3 ± 2\sqrt{3} ← exact solutions

6 0
3 years ago
For the polynomial function ƒ(x)= −2x2 − 4x + 16, find all local and global extrema.
rusak2 [61]

For the given quadratic equation we only have a maximum at y = 18.

<h3>How to find the extrema of the given function?</h3>

Here we have:

f(x) = -2x^2 - 4x + 16

Notice that this is a quadratic equation of negative leading coefficient.

Then we have a maximum at the vertex, and both arms tend to negative infinity as x tends to infinity or negative infinity.

The vertex is at:

x = -(-4)/(2*(-2)) = -1

The maximum is:

f(-1) = -2*(-1)^2 - 4*(-1) + 16 = -2 + 4 + 16 = 18

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
-1/2+4×^3+3×+x^4-x^5
Misha Larkins [42]
The answer is going to be 29444
8 0
3 years ago
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