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ollegr [7]
3 years ago
6

What does r equal in 4r+5=3r

Mathematics
1 answer:
vekshin13 years ago
5 0
4r+5=3r can also be written
4r=3r-5
1r=-5
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How are ∠1 and ∠2 related
andreyandreev [35.5K]

Answer:

  • D. They are adjacent

Step-by-step explanation:

Angles 1 and 2 have common side, so they are adjacent. They are not making a right or straight angle.

Correct choice is D

7 0
2 years ago
Is f = 3 a solution to the inequality below?
Nataliya [291]

Answer: Yes

Step-by-step explanation:

f=3

11+3= 14

23 > 14

es correcto decir que 23 es mas grande que 11+f

3 0
3 years ago
n parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m. What are the values of x and y? x = 10, y
seropon [69]

Answer:

The value of x = 11  and y = 2

Step-by-step explanation:

Given : parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m.

We have to find values of x and y.

Let P be the point of intersection of diagonals OM and LN.

In a parallelogram diagonal  bisects at right angles  and point of intersection divide diagonal in equal parts.

Thus, OP = MP and LP = PN

OP = MP , substitute the values, we get,

(2x-1) =  21

⇒ 2x = 22

⇒  x = 11

LP = PN , substitute the values, we get,

y + 3 = 3y -1

⇒  3y - y = 4

⇒  2y = 4

⇒ y = 2  

Thus, the value of x = 11  and y = 2


8 0
3 years ago
An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

800000\sqrt{(3 - d)^2 + 4}

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

800000\sqrt{(3 - d)^2 + 4} + 400000d

We can find the minimum value of this by taking the 1st derivative and set it to 0

800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0

We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

\sqrt{(3 - d)^2 + 4} = 6 - 2d

From here we can square up both sides

(3 - d)^2 + 4 = (6 - 2d)^2

9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

3d^2-18d+27 = 0

d^2 - 6d + 9 = 0

(d - 3)^2 = 0

d -3 = 0

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0
3 years ago
T 3.7.4 Quiz: Working With the Di
koban [17]

Answer:

A

Step-by-step explanation:

3 0
2 years ago
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