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Rashid [163]
3 years ago
9

which statements are true about the fully simplified product of (b – 2c)(–3b c)? check all that apply. the simplified product ha

s 2 terms. the simplified product has 4 terms. the simplified product has a degree of 2. the simplified product has a degree of 3. the simplified product has a degree of 4. the simplified product, in standard form, has exactly 2 negative terms.
Mathematics
2 answers:
kicyunya [14]3 years ago
6 0
(b-2c)(-3b+c)=-3 b^{2} +bc+6bc-2 c^{2} =-3 b^{2} +7bc-2 c^{2}
The simplified product has a degree of 2.
The simplified product, in standard form has exactly 2 negative terms.
harkovskaia [24]3 years ago
6 0

Answer:

3. The simplified product has a degree of 2.

6. The simplified product, in standard form has exactly 2 negative terms.

Step-by-step explanation: This answer is 100% correct for edge.nuity.

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the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
Abe spent $144.00 for four bags of grass seed. How much did he spend on each bag
EastWind [94]

Answer:

Abe spent 36 dollars on each bag

Step-by-step explanation:

divide 144 by 4 (because there are 4 bags in total, and he spent 144 dollars)

the answer will be 36

3 0
3 years ago
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Mr. Huyck needs 8 gallons of punch for the school dance. How many<br> quarts of punch would he need?
koban [17]
32 bc eight times four equals 32
8 0
3 years ago
Read 2 more answers
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
What is the surface area of the square pyramid represented by the net? 9 m Enter your answer in the box 6 m 9m 6 m 9 m m 9 m​
Darya [45]

Answer:

144

Step-by-step explanation:

On this shape we are going to splt up the 4 triangles for the square to make it simple.

So, firstly, plug is the h an w of one of the triangles into the formula for the area of a triangle which is hxw/2

H=9

W=6

9x6/2=27

Then multiply the area of the triangle, 27, to get the total area of all 4 triangles (since they all have the same measurements)

27x4=108

108 is the area of all 4 triangles

Next, just put the l and w into the equation for the area of a square which is lxw

L=6

W=6

6x6=36

36 is the area of the square

Lastly, just add the areas of the triangles and the square together

108+36=144

144 is the total area/surface area, of the pyramid

5 0
2 years ago
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