Assuming that he read at the same speed last summer, 2,724 pages.
First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
B.) 2,4,8,16,32 is the geometric series as the common ratio is equal for each step
Step-by-step explanation:
sum of the ratio=3+3+4=10
now,
angle I = 3/10×180=54
angle II= 3/10×180=54
angle III=4/10×180=72
that shows th given triangle is isoceles