Answer:
Time = 12.27seconds
Explanation:
Given
Speed = 25miles/hour
Distance = 150 yards = 150(0.000568182)miles
Distance (in miles) = 0.0852273miles
Get the time
Speed = Distance/Time
Time = Distance/Speed
Time = 0.0852273/25
Time = 0.0034hours
Time = 0.0034 * 3600secs
Time = 12.27seconds
Answer:
The <u>water vapor</u> will have the greatest entropy at the triple point
Explanation:
At the triple point of water, which has the properties of 0.0075°C temperature and 6.11657 mbar pressure, solid ice, liquid water and water vapor exist together in a location
According to Professor Stephen Lower on LibreTexts website entropy is a measure the extent to which thermal energy is shared and spread in a system
The change in entropy, ΔS = ΔH/T
The heat change in = 6.01 kJ/mol
The heat change in vaporization, = 45.05 kJ/mol
The heat change in sublimation, = 51.06 kJ/mol
Therefore, the entropy of the water vapor > The entropy of liquid water, > The entropy of the solid ice,
The portion with the highest entropy at the triple point is the water vapor
The water vapor will have the greatest entropy at the triple point
Answers:
a) 13 s
b) 0.362 m/s
Explanation:
We have the following data:
is the mass of the mass damper
is the length of the pendulum
is the amplitude
<h3>a) Period of oscillation:</h3>
This can be solved by the following equation:
(1)
Where:
is the period
is the acceleration due gravity
(2)
(3)
<h3>b) Maximum Velocity:</h3>
The velocity in a pendulum is maximum when the pendulum is in its mean position and the amplitude is maximum. So, the equation in this case is:
(4)
(5)
Answer:
f = - 20 cm
Explanation:
This exercise asks us for the focal length, which for a lens in air is
1 / f = (n₂-n₁) (1 / R₁ - 1 / R₂)
where n₂ is the refractive index of the material, n₁ is the refractive index of the medium surrounding the lens, R₁ and R₂ are the radii of the two surfaces.
In this exercise the medium that surrounds the lens is air n₁ = 1 and the lens material has an index of refraction n₂ = n = 1.50, let's substitute in the expression
- 1/40 = (n-1) (1 / R₁ -1 / R₂)
(1 / R₁ - 1 / R₂) = - 1/40 (n-1)
let's calculate
(1 / R₁ -1 / R₂) = - 1/40 (1.50 -1)
(1 / R₁ -1 / R₂) = -1/20
Now we change the construction material for one with refractive index
n = 2, keeping the radii,
1 / f = (n-1) (1 / R₁-1 / R₂)
1 / f = (n-1) (-1/20)
let's calculate
1 / f = (2.00-1) (-1/20)
1 / f = -1/20
f = - 20 cm