Answer:
Complete question:
c.If the current in the second coil increases at a rate of 0.365 A/s , what is the magnitude of the induced emf in the first coil?
a.
b.flux through each turn = Ф = 
c.magnitude of the induced emf in the first coil = e= 
Explanation:
a. rate of current changing = ![\frac{di}{dt}=[tex]M=\frac{1.60\times10^{-3} V}{0.240\frac{A}{s} }}](https://tex.z-dn.net/?f=%5Cfrac%7Bdi%7D%7Bdt%7D%3D%5Btex%5DM%3D%5Cfrac%7B1.60%5Ctimes10%5E%7B-3%7D%20V%7D%7B0.240%5Cfrac%7BA%7D%7Bs%7D%20%7D%7D)
[/tex]
Induced emf in the coil =e= 
For mutual inductance in which change in flux in one coil induces emf in the second coil given by the farmula based on farady law
b.
Flux through each turn=?
Current in the first coil =1.25 A
Number of turns = 20
using MI = NФ
flux through each turn = Ф = 
flux through each turn = Ф =
c.
second coil increase at a rate = 0.365 A/s
magnitude of the induced emf in the first coil =?
using 
magnitude of the induced emf in the first coil = e=
The mass of the first block will be three times the mass of the second block.
According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;
F is the acting force
m is the mass
a is the acceleration of the body
Given the following parameters
Constant force F = 1N
For the first block with the acceleration of "a"
1 = m₁a
a = m₁/1
m₁ = a .................1
For the second block, acceleration is thrice that of the first. This means;
F = m(3a)
1 = 3ma
..........................2
Divide both equations
From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.
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