The step in the nitrogen that is accelerated at the beginning of the eutrophication process is producer uptake of nitrogen. The correct answer is C.
Answer: His and Lys are deprotonated but Asp will be protonated.
Explanation:
As the pH is given as 7.4 and pK of His is given as 6.00. There will occur a positive charge on His when it's pH < pK therefore, it is neutral at the given pH.
As the pK value of Lys is 10.53 that is greater than the pH of 7.40. Therefore, charge on Lys is positive.
As the pK value of Asp is 3.65 which is less than the pH value of 7.40. Hence, Asp has a negative charge.
Therefore, we can conclude that His and Lys are deprotonated but Asp will be protonated.
Answer:
The volume is
<h2>180 mL</h2>
Explanation:
In order to solve for the volume we use the formula for Boyle's law which is
<h3>
</h3>
where
P1 is the initial pressure
V1 is the initial volume
P2 is the final pressure
V2 is the final volume
Since we are finding the final volume we are finding V2
Making V2 the subject we have
<h3>
</h3>
From the question
P1 = 300 mmHg
V1 = 300 mL
P2 = 500 mmHg
Substitute the values into the above formula and solve for the final volume obtained
That's
<h3>
</h3>
We have the final answer as
<h3>180 mL</h3>
Hope this helps you
Answer:
As with the hydrogen-ion concentration, the concentration of the hydroxide ion can be expressed logarithmically by the pOH. The pOH of a solution is the negative logarithm of the hydroxide-ion concentration. pOH=−log[OH−] The pH of a solution can be related to the pOH.
