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aniked [119]
4 years ago
7

PLZ HELP!! I WILL GIVE BRAINLIEST!! 50+PTS!! PLZ HELP!!!! In an exothermic reaction at equilibrium, what is the effect of loweri

ng the temperature? A. The reaction makes more products. B. The reaction makes more reactants. C. The reaction is unchanged.
Chemistry
2 answers:
IgorC [24]4 years ago
8 0

Answer:

A. your reaction makes more products.

Explanation:

This is a fun question dealing with idea of Le Chatelier's principle.

In an exothermic reaction, you produce heat. This means that heat will act as a product (or be on the product side).

Suppose there's an imaginary equation:

A + B -----> C (Now if I lower the amount of B, the equilibrium will shift to left to make up the lost B, or to bring the system back to equilibrium)

Apply the same concept as above below:

A + B -------> C + Heat (as I mentioned, since this is exothermic reaction heat is written as product, so if you lower the temperature, which means basically lower the heat, the reaction will shift towards right to make up the lost heat, in this process you will make extra C which is products. Thus, your reaction makes more products.

Vilka [71]4 years ago
4 0

Answer:

reaction makes more product

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2 KClO2 (s) 0 2 KCl (s) + 3 02 (g)
Nonamiya [84]

Volume of O2 : 168 L

<h3>Further explanation</h3>

Given

Reaction

2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)

5 moles of KCIO3

Required

volume of O2

Solution

From the equation, mol O2 :

= 3/2 x moles KClO3

= 3/2 x 5 moles

= 7.5 moles

Assumed at STP( 1 mol = 22.4 L) :

= 7.5 x 22.4 L

= 168 L

5 0
3 years ago
Which solution below would turn litmus paper red?
Assoli18 [71]
Litmus paper turns red in acidic conditions whether its blue or red litmus ,its not NH3 (ammonia)  , neither is it barium hydroxide (A)  , sodium hydroxide (B) will make it blue or remain blue (depemding on type of paper used ) so it has to be D which is the chemjcal formula for acetic acid , hope this helps ! 
7 0
4 years ago
What is the concentration of a solution with 2.00 moles of solute in 4.00 l of solution?
jarptica [38.1K]

Explanation:

Molarity is defined as the the number of moles present in a solution divided by volume in liters.

Mathematically,    Molarity = \frac{/text{no. of moles}}{volume in liter}

As it is given that number of moles present into the solution are 2.00 moles and volume is 4 liter. Therefore, calculate the molarity of solution as follows.

                Molarity = \frac{/text{no. of moles}}{volume in liter}

                          = \frac{2.00 moles}{4.00 L}

                          = 0.5 M

Thus, we can conclude that the concentration of given solution is 0.5 M.

6 0
3 years ago
Xg of U and 3.795 g of O combine to form 20.00 g of
Deffense [45]

The percent composition of Uranium in U308 = C. 81.03%

<h3>Further explanation</h3>

Given

X g of U

3.795 g of O

20.00 g of  U308

Required

The percent composition of Uranium

Solution

mass of Uranium in U308 :

= mass of U308 - mass of O

= 20 g - 3.795 g

= 16.205 g

The percent composition :

\tt \%U=\dfrac{mass~U}{mass~U308}\times 100\%

%U = (mass U/mass U308) x 100%

%U= (16.205/20) x 100%

%U = 81.025≈81.03

8 0
3 years ago
what is the final molarity of a dilute solution of NaOH that is prepared by pipetting 5.00 mL of 7.00 M NaOH into a 100mL volume
Angelina_Jolie [31]

Answer:

M_{diluted}=0.35M

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}

Clearly, the concentrated solution is 7.00M and the diluted solution is unknown, thus, the concentration of the diluted solution after the dilution to 100 mL is:

M_{diluted}=\frac{M_{concentrated}V_{concentrated}}{V_{diluted}} =\frac{7.00M*5.00mL}{100mL}\\ \\M_{diluted}=0.35M

Best regards.

4 0
4 years ago
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