Answer:
3m/s
Explanation:
Data obtained from the question include:
Initial speed (s1) = 4 m/s
Final speed (S2) = 7m/s
Change in speed (ΔS)
ΔS = s2 — s1
ΔS = 7 — 4
ΔS = 3m/s
Therefore, the change in speed is 3m/s
I believe the answer is B. a million or more.
<u>The </u><u>emperical formula </u><u>can be </u><u>calculated </u><u>as follows:</u>
<u>mass :</u> 4.12g of N and 0.88g of H
<u>moles:</u> 4.12g/14.007 and 0.88g/1.008
<u>moles:</u> 0.294 and 0.873
<u>moles/smallest number</u>: (gives the ratio of atoms)
0.294/0.294 and 0.873/0.294
1 and 2.969
1 and 3
The simplest ratio of N : H is 1 : 3
<u>Hence the </u><u>emperical formula </u><u>is </u><u>NH3</u>
<u>Explanation:</u>
1. The emperical formula can be found by getting the <u>simplest ratio of atoms in a molecule.</u>
2. To get the simplest ratio of atoms we find out the <u>number of moles of each atoms in it.</u>
3. From the number of moles of atoms we can find the simplest ratio of each atom by dividing the <u>number of moles by the smallest number.</u>
An organ system is contained inside an organism. Going from largest to smallest it goes organism->organ system-> organ-> tissue-> cell-> atom
Question:
What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?
a. disaccharide
b. carboxylic acid
c. hemiacetal
d. ester
e. stereoisomer
Answer:
hemiacetal forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group
Explanation:
It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.