1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aniked [119]
4 years ago
7

PLZ HELP!! I WILL GIVE BRAINLIEST!! 50+PTS!! PLZ HELP!!!! In an exothermic reaction at equilibrium, what is the effect of loweri

ng the temperature? A. The reaction makes more products. B. The reaction makes more reactants. C. The reaction is unchanged.
Chemistry
2 answers:
IgorC [24]4 years ago
8 0

Answer:

A. your reaction makes more products.

Explanation:

This is a fun question dealing with idea of Le Chatelier's principle.

In an exothermic reaction, you produce heat. This means that heat will act as a product (or be on the product side).

Suppose there's an imaginary equation:

A + B -----> C (Now if I lower the amount of B, the equilibrium will shift to left to make up the lost B, or to bring the system back to equilibrium)

Apply the same concept as above below:

A + B -------> C + Heat (as I mentioned, since this is exothermic reaction heat is written as product, so if you lower the temperature, which means basically lower the heat, the reaction will shift towards right to make up the lost heat, in this process you will make extra C which is products. Thus, your reaction makes more products.

Vilka [71]4 years ago
4 0

Answer:

reaction makes more product

You might be interested in
What are smart cancer treatments
natita [175]

Is a potential to provide effective treatment with fewer side effects than a traditional therapy.

3 0
3 years ago
How many moles are in 4.5 g of<br> Sodium Chloride, NaCl?
Sergeu [11.5K]

Answer:

The answer to the question is 0.07 moles

6 0
3 years ago
How does increasing the temperature affect collisions?
ddd [48]
Combustion Have a great day!
8 0
3 years ago
Read 2 more answers
HELP PLEASE!! ASAP What would the mass be in kg?
fgiga [73]

Answer:

i guess answer is 0.0600

Explanation:

Here,

Density=0.791g/cm^3

Volume=75.89ml

So,

Mass=Density*Volume

=0.791g/cm^3×75.89ml

=60.02g/cm^3.ml

Expressing them in kg

60.02/1000

=0.0600 kg

4 0
3 years ago
What is a chemical treatment process used to remove dissolved ionic species from contaminated aqueous streams?
NeTakaya

Answer:

Ion exchange.

Explanation:

One of the ways in which water can be treated is through the process known as ION EXCHANGE. Using this for treating water has to do basically with the transfer or say the exchange of ions.

Ion exchanges is done by exchanging ions which are considered as 'unfit' or contaminants by the ones that are "fit".

Ions from what is known as zeolite or resin is been exchanged with the ions in the water. Cations are exchanged with cations and anions are exchanged with anions.

NB: this method is a good method or removing contaminants that are ions but not contaminants that are not ions.

6 0
3 years ago
Other questions:
  • Pesticide concentrations in the Rhine River between Germany and France between 1969 and 1975 averaged 0.55 mg/L of hexachloroben
    7·1 answer
  • What is the first step in replication
    5·1 answer
  • What element is in group 17 and period 2 of the periodic table?
    14·1 answer
  • How does density differ from concentration?
    6·1 answer
  • Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H
    10·1 answer
  • Each element has a different:
    10·1 answer
  • Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
    8·1 answer
  • How would you describe the connection between the amount of energy a type of electromagnetic wave has and how that wave is used
    15·1 answer
  • Why is air considered a solution?
    10·1 answer
  • What is diffusion?<br>Class 9th <br>Chemistry <br><br><br><br><br>​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!