Answer:
Equilibrium shifts to the right
Explanation:
An exothermic reaction is one in which temperature is released to the environment. Hence, if the reaction vessel housing an exothermic reaction is touched after reaction completion, we will notice that the reaction vessel e.g beaker is hot.
To consider the equilibrium response to temperature changes, we need to consider if the reaction is exothermic or endothermic. In the case of this particular question, it has been established that the reaction is exothermic.
Heat is released to the surroundings as the reactants are at a higher energy level compared to the products. Hence, increasing the temperature will favor the formation of more reactants and as such, the equilibrium position will shift to the left to pave way for the formation of more reactants. Thus , more acetylene and hydrogen would be yielded
<span>A cell membrane protects the structures within the cell. They are semipermeable which means that only certain objects are able to pass through them. They also give shape to the cell and support its structure. </span>
Calculating K from Known Initial Amounts and the Known Change in Amount of One of the Species<span>Write the equilibrium expression for the reaction.Determine the molar concentrations or partial pressures of each species involved.<span>Determine all equilibrium concentrations or partial pressures using an ICE chart.</span></span>
<u>Answer:</u> Step 2 in the given mechanism is the rate determining step
<u>Explanation:</u>
In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.
The intermediate reaction of the mechanism follows:
<u>Step 1:</u> 
<u>Step 2:</u> 
As, step 2 is the slow step. It is the rate determining step
Rate law for the reaction follows:
![\text{Rate}=k[O_3][O]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BO_3%5D%5BO%5D)
Hence, step 2 in the given mechanism is the rate determining step
