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Nezavi [6.7K]
3 years ago
13

The electron stable state configuration in atoms is best seen in the ______ configuration.

Chemistry
1 answer:
mamaluj [8]3 years ago
8 0
<span>The electron stable state configuration in atoms is best seen in the inert gas configuration.
Inert gas are the most stable since they have their valence electron shell saturated with electrons (the valence shell has the maximum number of electrons it can hold). They need neither donate nor accept electrons.</span>
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Define saturated and unsaturated fats​
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SATURATED: Saturated fat is a type of fat in which the fatty acid chains have all or predominantly single bonds.

UNSATURATED: Unsaturated fats are loosely packed. They tend to be liquid at room temperature.

<em>There are two main types of unsaturated fat:</em>

<u>Monounsaturated</u>

<u>Polyunsaturated</u>

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2 years ago
When the electron of a hydrogen atom moves into a higher energy orbit, what is the state of the atom?
faltersainse [42]
Answer is: <span>excited state.
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2 years ago
Atoms on the left side of the periodic table tend to form positive ions because
professor190 [17]
They all lose electrons
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2 years ago
A light year is equal to <br><br> 5,866,000<br><br> 5,866<br><br> 5,866,000,000,000<br><br> 5.866
Fynjy0 [20]
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7 0
3 years ago
Read 2 more answers
The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding
slega [8]

Answer:

Binding\ energy=43.43\times 10^{-20}\ J

Explanation:

Using the expression for the photoelectric effect as:

E=h\nu_0+\frac {1}{2}\times m\times v^2

Also, E=\frac {h\times c}{\lambda}

\nu_0=\frac {c}{\lambda_0}

Applying the equation as:

\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

Given, \lambda=4.00\times 10^{-7}\ m

\frac {hc}{\lambda_0} is the binding energy or threshold energy

\frac {1}{2}\times m\times v^2 is the kinetic energy of the electron emitted.  = 6.26\times 10^{-20}\ J

Thus, applying values as:

\frac{h\times c}{\lambda}=Binding\ Energy+Kinetic\ Energy

\frac{6.626\times 10^{-34}\times 3\times 10^8}{4.00\times 10^{-7}}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

\frac{19.878}{10^{19}\times \:4}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

49.69\times 10^{-20}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

Binding\ energy=43.43\times 10^{-20}\ J

5 0
3 years ago
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