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1 year ago

at 530.4 mmhg and 55.3oc, a 3.14-l sample of a hydrocarbon gas has a mass of 2.28 g. what is the formula of the gas?

1 answer:

6 0

The number of moles of the hydrocarbon gas is 0.081. FRom this the molecular weight is calculated as 28 g/mol. The formula of hydrocarbon having this molecular weight is ethene, C₂H₄.

<h3>What is ethene?</h3>

Ethene is an unsaturated hydrocarbon thus it have a double bond with the formula C₂H₄. It is written as CH₂=CH₂ .

It is given that the pressure of the system is 53.4 mmhg that is 0.69 atm and temperature of the system is 55.3 degree celsius that is 328.3 K and volume is 3.14 L.The universal gas constant is 0.082 L atm (K mol). Apply these values in ideal gas equation.

PV = nRT

n = PV/RT

= (0.69 atm × 3.14 l) / (0.082 L atm (K mol) ) × 328.3 K

= 0.08 mole.

The molecular weight of this gas is 2.28 /0.08 =28 g/mol.

Hence, a hydrocarbon gas with a mass of 28 g/mol is ethene C₂H₄ .

To find more about ethene, refer the link below:

brainly.com/question/2720922

#SPJ1

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First, convert 735 torr to atm. Divide by 760.
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