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yarga [219]
3 years ago
9

Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass i

n the center. A force of 50 N pushes on the 5.0-kg box, which pushes against the other two boxes. What magnitude force does the 5.0-kg box exert on the 3.0-kg box?

Physics
1 answer:
Fed [463]3 years ago
6 0

Answer:25 N

Explanation:

Given

mass of 5 , 3 & 2 kg blocks lie on floor

Force on 50 N pushes the 5 kg box

Let N_1 be the reaction on 2 kg box therefore

N_1=2\times a

where a is the acceleration of the system

N_2=reaction on 3 kg block by 5 kg block

N_2-N_1=3a

N_2=5a

Now for 5 kg block

F-N_2=5a

F=10a

a=\frac{F}{10}=5 m/s^2

Force exerted by 5 kg block on 3 kg block is

N_2=5\times 5=25 N

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Rewriting the equation with the given values:

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