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leva [86]
2 years ago
15

Which force below does the most work? All three displacements are the same. The 10 N force. The 8 N force The 6 N force. They al

l do the same work. Sin60º = 0.87 cos60º = 0.50
Physics
1 answer:
Daniel [21]2 years ago
5 0

THe question is missing parts. Here is the complete question.

Which force below does the most work? All three displacements are the same.

A. The 10 N force

B. The 8 N force

C. The 6 N force

D. They all do the same work

note: sin60° = 0.87

        cos60° = 0.5

Answer: C. The 6 N force

Explanation: <u>Work</u> <u>(</u>τ<u>)</u> is the transfer of energy to or from a system by moving an object.

Work is dependent of the force we applied to the object, the displacement it creates and the angle between the force and the displacement. In other words:

\tau = F.d.cos \theta

and its unit is joule [J].

For the 10 N force, angle is 90°. Cosine of 90° is 0. Therefore:

\tau = 10.d.cos 90

\tau = 0

For the 8 N force, angle is 60°. Then:

\tau = 8.d.cos 60

\tau = 8d(0.5)

\tau = 4d

For the 6 N force, angle is 0, because vectors displacement and force are pointing to the same direction:

\tau = 6.d.cos 0

\tau=6d(1)

\tau= 6d

Comparing the work done, the force that does the most work is force 6N.

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If two equal forces act on an object in opposite directions, what is the net
labwork [276]

Answer:

Net Force = 0

Explanation:

Causes objects to accelerate. Balanced Forces. Two equal forces push in opposite direction causing no change in motion causing net force = 0.

4 0
3 years ago
P*V = n*R*T where P = pressure V = volume n = number of moles R = the universal gas constant T = temperature in degrees Kelvin T
seraphim [82]

The Gay-Lussac's law or Amonton's law states that the pressure of a given amount of a gas is directly propotional to its temperature if its volume is kept constant  .

            P∝T

and  

The Charles Law states that volume of given amount of gas at constant pressure  is directly propotional to temperature.

              V∝T

So, by Gay-Lussac's law if we increase the temperature the Pressure will increase and by Charles Law, if we increase the temperature the volume will increase.

Therefore, if the temperature of gas increases either the pressure of the gas, the volume of the gas, or both, will increase.

Hence,

Answer is option C

3 0
3 years ago
Read 2 more answers
A light beam travels at 1.94×108 in quartz. The wavelength of the light in quartz is 355 .Part AWhat is the index of refraction
Alja [10]

A) 1.55

The speed of light in a medium is given by:

v=\frac{c}{n}

where

c=3\cdot 10^8 m/s is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

v=1.94\cdot 10^8 m/s

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

\lambda=\frac{\lambda_0}{n}

where

\lambda is the wavelenght in quartz

\lambda_0 is the wavelength in air

n is the refractive index

For the light in this problem, we have

\lambda=355 nm\\n=1.55

Therefore, we can re-arrange the equation to find \lambda_0, the wavelength in air:

\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm

4 0
3 years ago
The voltage across the input terminals of a transformer is 120 V. The primary has 25 loops and the secondary has 50 loops. The v
saw5 [17]

Answer:

240 V

Explanation:

Vp = 120 V

Np = 25

Ns = 50

Vs = ?

Vs / Vp = Ns / Np

Vs / 120 = 50 / 25

Vs / 120 = 2

Vs = 240 V

5 0
3 years ago
A) the unstretched length of each elastic rope is 24m. The rope obeys hookes law. The vertical distance between P and Q is 35m.
solong [7]

Explanation:

a) The rope obeys Hooke's law, so:

F = k Δx

The elastic energy in the rope is:

EE = ½ k Δx²

Or, in terms of F:

EE = ½ F Δx

Use trigonometry to find the stretched length.

cos 20° = 35 / x

x =  37.25

So the displacement is:

Δx = 37.25 − 24

Δx = 13.25

The elastic energy per rope is:

EE = ½ (3.7×10⁴ N) (13.25 m)

EE = 245,000 J

There's two ropes, so the total energy is:

2EE = 490,000 J

Rounded to one significant figure, the elastic energy is 5×10⁵ J.

b) The elastic energy in the ropes is converted to gravitational energy.

EE = PE = mgh

5×10⁵ J = (1.2×10³ kg) (9.8 m/s²) h

h = 42 m

Rounded to one significant figure, the height is 40 m.  So the claim is not justified.

6 0
2 years ago
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