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AnnyKZ [126]
3 years ago
9

What is t=3seconds in scrience

Physics
1 answer:
alekssr [168]3 years ago
8 0
Well....t usually stands for time and the unit seconds proves that
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x=50

Explanation:

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A piston–cylinder device initially contains steam at 3.5 MPa, superheated by 5°C. Now, steam loses heat to the surroundings and
velikii [3]

<u>Answer :</u>

(a) The Initial temperature of the steam is 247.557°C

(b) The enthalpy change per unit mass of the steam is -1771 kJ/kg

(c) The final pressure is 1555 kPa, and the liquid vapor mixture contains small mass of vapor.

<u>Explanation :</u>

From the given statements, we know

Initial steam pressure (P_1) = 3.5 MPa

Degree of Super heat = 5°C

Saturation Temperature (T_s_a_t) = 242.557°C [From Steam Table]

Now, the Initial temperature (T_1) of steam is given by-

T_1 = T_s_a_t + Degree of Superheat

 = 242.557 + 5 = 247.557°C

(b)To find: The enthalpy change per unit mass of the steam is  

We know enthalpy (h) change is given by

Δh = h_2 – h_1

From steam Table, properties of the gas at state 1 and state 2  

h_1 = 2821.1 kJ/kg

h_2 = 1049.7 kJ/kg

On substituting the values, we get

or, Δh = 1049.7 - 2821.1 = -1771 kJ/kg

(c) To Find: The final pressure of the liquid vapor mixture contains small mass of vapor.

We find that the gas at the final position, i.e., at position 3

Final Temperature (T_3) = 200°C [Given] ……………………………..(1)

Specific Volume (v_3) = Specific Volume (v_2) = 0.00123 m^3/kg ….....(2)

Using steam table for corresponding values of (1) and (2), we get

Final Pressure P_3 = 1555 kPa

Dryness fraction (x_3) = 0.0006.

6 0
3 years ago
Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitu
ANEK [815]

Answer:

The electric field will be decreased by 29%

Explanation:

The distance between point P from the distance z = 2.0 R

Inner radius = R/2

Outer raidus = R

Thus;

The electrical field due to disk is:

\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big))

\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)

Similarly;

\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)

However; the relative difference is: \dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o  \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}

\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}

= 0.2828 \\ \\ \mathbf{\simeq  29\%}

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3 years ago
The transfer of energy through varios stages in an ecological community is called
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It is called food chain
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