All categories

3 years ago

What is Minimum Threshold Frequency?

Physics

2 answers:

tatiyna3 years ago

8 0

Answer:

The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely.

Lady bird [3.3K]3 years ago

4 0

the minimum frequency of radiation that will produce a photoelectric effect.

You might be interested in

Given a force of 100 N and a acceleration of 5 m/s, what is the mass

SIZIF [17.4K]

Answer:

$force = mass \times acceleration \\ 100 = m \times 5 \\ m = \frac{100}{5} \\ m = 20 \: kg$

8 0

2 years ago

Read 2 more answers

A thin rod of length 0.64 m and mass 120 g is suspended freely from one end. It is pulled to one side and then allowed to swing

valina [46]

Answer:

1. Kinetic Energy = 0.0161 Joules

2. Height = 0.0137m

Explanation:

Given

Length of Rod, l = 0.64m

Mass, m = 120g = 0.12kg

Angular speed, w = 1.40 rad/s

Calculating the Rod's kinetic energy

This is calculated by

Kinetic Energy = ½Iw²

Where I = rotational inertia of the rod about an axis.

This is calculated as follows;

I = Icm + mh²

I = ImL² + m(L/2)²

I = 1/12 * 0.12 * 0.64² + 0.12 * (0.64/2)²

I = 0.016384 kgm²

By substituton

KE = ½Iw² becomes

KE = ½ * 0.016384 * 1.40²

KE = 0.01605632J

KE = 0.0161 Joules

2. Using the total conservation of momentum;

K + U = Kf + V

Where K = Initial Kinetic Energy of the rod at lowest point.

U = Initial gravitational potential energy of the rod at lowest point

Kf = Final Kinetic Energy of the rod at maximum height = 0 J

V = Final gravitational potential energy of the rod at maximum height

So, K + U = Kf + V become

K + U = 0 + V

K + U = V

K = V - U = mgh

substitute 0.01605632J for K

0.01605632J = mgh

h = 0.01605632J/mg

h = 0.01605632J/(0.12 * 9.8)

h = 0.013653333333333

h = 0.0137m

4 0

3 years ago

What force is needed to move a barrel 45-m if 3600 J of work are accomplished?

lesantik [10]

Answer:

<h3>The answer is 80 N</h3>

Explanation:

The force acting on the object can be found by using the formula

$f = \frac{w}{d} \\$

where

d is the distance

w is the work done

We have

$f = \frac{3600}{45} \\$

We have the final answer as

Hope this helps you

8 0

3 years ago

The sun continuously radiates energy into space, some of which is intercepted by the earth. The average temperature of the surfa

Xelga [282]

Answer: Because of the reflects back into space equal amount of radiation as it receives.

Explanation: The Earth's temperature doesn't keep rising because as the Earth receives the radiation from the sun, the Earth reflects back an equal amount of that radiation back to space.

This reflective ability of a planet of the sun radiation incident on it is known as the albedo.

4 0

3 years ago

A car tire contains 0.0380m3 of air at a pressure of 2.20×105N/m2 (about 32 psi). How much more internal energy does this gas ha

emmasim [6.3K]

Answer:

$\Delta U = 11305 J$

Explanation:

As per ideal gas equation we know that

PV = nRT

here we know that

$P = 2.20 \times 10^5 Pa$

$V = 0.0380 m^3$

now we have

$nRT_1 = (2.20 \times 10^5)(0.0380) = 8360 J$

now for other case at zero gauge pressure we have

$P = 1.01 \times 10^5 Pa$

$V = 0.0380 m^3$

we have now

$nRT_2 = (1.01 \times 10^5)(0.0380) = 3838 J$

now the difference in internal energy of air is given as

$\Delta U = \frac{5}{2}nR\Delta T$

$\Delta U = \frac{5}{2}(8360 - 3838)$

$\Delta U = 11305 J$

6 0

3 years ago

What is Minimum Threshold Frequency?​

What is Minimum Threshold Frequency?