The table lists the mass and charge of a proton and a neutron.
2 answers:
The gravitational force is much larger than the electrical force for any distance between the particles.
Explanation:
The gravitational force between two particles is given by:
where
G is the gravitational constant
m1, m2 are the masses of the two particles
r is the separation between the two particles
The electric force between two particles is given by:
where
k is the Coulomb's constant
q1, q2 are the charges of the two particles
r is the separation between the two particles
In this problem, we are comparing the gravitational force and the electric force between a proton and a neutron.
We must immediately notice that the charge of the neutron is zero, since it is electrically neutral:
q = 0
This means that the electric force between the proton and the neutron is always zero, regardless of their distance. And therefore, since their masses is not zero (and the gravitational force is never zero), the correct answer is
The gravitational force is much larger than the electrical force for any distance between the particles.
Learn more about gravitational force:
About electrical force:
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Answer:
X-Positions: Y-Positions
x(0) = 0 y(0) = 0
x(2) = 120 m y(2) = 19.6 m
x(4) = 240 m y(4) = 78.4 m
x(6) = 360 m y(6) = 176.4 m
x(8) = 480 m y(8) = 313 m
x(10) = 600m y (10) = 490 m
Explanation:
X-Positions
- First, we choose to take the horizontal direction as our x-axis, and the positive x-axis as positive.
- After being thrown, in the horizontal direction, no external influence acts on the stone, so it will continue in the same direction at the same initial speed of 60. 0 m/s
- So, in order to know the horizontal position at any time t, we can apply the definition of average velocity, rearranging terms, as follows:
- It can be seen that after 2 s, the displacement will be 120 m, and each 2 seconds, as the speed is constant, the displacement will increase in the same 120 m each time.
Y-Positions
- We choose to take the vertical direction as our y-axis, taking the downward direction as our positive axis.
- As both axes are perpendicular each other, both movements are independent each other also, so, in the vertical direction, the stone starts from rest.
- At any moment, it is subject to the acceleration of gravity, g.
- As the acceleration is constant, we can find the vertical displacement (taking the height of the cliff as the initial reference level), using the following kinematic equation:
- Replacing by the values of t, we get the following vertical positions, from the height of the cliff as y = 0:
- y(2) = 2* 9.8 m/s2 = 19.6 m
- y(4) = 8* 9.8 m/s2 = 78.4 m
- y(6) = 18*9.8 m/s2 = 176.4 m
- y(8) = 32*9.8 m/s2 = 313.6 m
- y(10)= 50 * 9.8 m/s2 = 490.0 m
Answer:
0.384c
Explanation:
To find the speed of the pursuit ship relative to the cruiser you use the following relativistic equation:
u': relative speed
u: speed of the pursuit ship = 0.8c
v: speed of the cruiser = 0.6c
c: speed of light
You replace the values of the parameters to obtain u':
Hence, the relative speed is 0.384c