The table lists the mass and charge of a proton and a neutron.
2 answers:
The gravitational force is much larger than the electrical force for any distance between the particles.
Explanation:
The gravitational force between two particles is given by:
where
G is the gravitational constant
m1, m2 are the masses of the two particles
r is the separation between the two particles
The electric force between two particles is given by:
where
k is the Coulomb's constant
q1, q2 are the charges of the two particles
r is the separation between the two particles
In this problem, we are comparing the gravitational force and the electric force between a proton and a neutron.
We must immediately notice that the charge of the neutron is zero, since it is electrically neutral:
q = 0
This means that the electric force between the proton and the neutron is always zero, regardless of their distance. And therefore, since their masses is not zero (and the gravitational force is never zero), the correct answer is
The gravitational force is much larger than the electrical force for any distance between the particles.
Learn more about gravitational force:
About electrical force:
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Answer:
vf = 3.27[m/s]
Explanation:
In order to solve this problem we must analyze each body individually and find the respective equations. The free body diagram of each body (box and bucket) should be made, in the attached image we can see the free body diagrams and the respective equations.
With the first free body diagram, we determine that the tension T should be equal to the product of the mass of the box by the acceleration of this.
With the second free body diagram we determine another equation that relates the tension to the acceleration of the bucket and the mass of the bucket.
Then we equalize the two stress equations and we can clear the acceleration.
a = 3.58 [m/s^2]
As we know that the bucket descends 1.5 [m], this same distance is traveled by the box, as they are connected by the same rope.
And the speed can be calculated as follows:
Answer:
12 m
Explanation:
The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:
where
s is the distance
u is the initial velocity
t is the time
a is the acceleration
For this problem,
and
u = 0, since we are considering the first second of motion
So, substituting t = 1 s, we find