Answer:
133.62 kmh.
Explanation:
Time provided = 3.25 hours.
Distance to be covered 300 km
Times spent in first 100 km = 1 hour
Time spent in next 43 km
= 43 / 40 = 1.075 hours
Total time spent = 2.075 hours
Total distance covered = 143 km
Distance remaining = 300 - 143
=157 km .
Time remaining = 3.25 - 2.075
= 1.175
Speed required = Distance remaining / time remaining
= 157 / 1.175
= 133.62 kmh.
Answer:
Your education back ground
Answer:
Time is 14.8 s and cannot landing
Explanation:
This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same
Calculate the time to stop, where it has zero speed
Vf² = Vo² + a t
t = - Vo² / a
t = - 110²/(-7.42)
t = 14.8 s
This is the time it takes to stop the jet
Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero
Vf² = Vo² + 2 to X
X = -Vo² / 2 a
X = -110² / 2 (-7.42)
X = 815.4 m
Since this distance is greater than the length of the runway, the jet cannot stop
Let's calculate the speed you should have to stop on a track of this size
Vo² = 2 a X
Vo = √ (2 7.42 800)
Vo = 109 m / s
It is conclusion the jet must lose some speed to land on this track
When a plane travels 395,000 meters in 9,000 seconds its speed is 395,000 ÷ 9000 = 43.888888 (the 8 repeats) meters per second.
Answer:
E = 0.93 10⁻⁶ N/C, 24º NorthEast
Explanation:
The electric force is related to the electric field by the relation
F = q E
where the bold letters indicate vectors and q is a scalar electric charge.
Using this equation the electric force is in the same direction as the electric field.
The magnitude of the field is
E = F / q
the charge they give us is q = 8.7 C
let's calculate
E = 8.1 10⁻⁶ / 8.7
E = 0.93 10⁻⁶ N / C
In summary, the magnitude of the electric field is E = 0.93 10⁻⁶ N/C and its direction is 24º NorthEast