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maks197457 [2]
3 years ago
15

Which statement best describes the common features of sound waves and light waves

Physics
1 answer:
Viktor [21]3 years ago
7 0
Sound waves or bounces off the wall and light waves are waves of light
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Assuming the density of the wine to be 1.0 g/ml, what caloric content does the alcohol (ethanol) in a 6-oz glass of wine (177 ml
viktelen [127]

mass = 177 x 1.0 g/mL= 177 g mass ethanol = 177 x 10.6/100 = 18.8 g moles = 18.8 g/46.069 g/mol = 0.408 1367 kJ/mol x 0.408 mol= 557.9 kJ

4 0
3 years ago
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the force between your feet and the floor is greater while standing on your tiptoes than while standing flat on your feet
Elodia [21]
Yes thats correct....becuase all of your weight is concentrated on a small area compared to the larger surface area of your feet!
is that what your question was?
4 0
3 years ago
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a ball rolls along the floor with a constant velocity of 3 m/s. How far will it have gone after 234 seconds?
sergij07 [2.7K]

Answer:

The ball travel for 702m

Explanation:

distance = speed × time

speed = 3m/s

time = 234s

distance = 3 × 234

= 702m

7 0
2 years ago
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Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard.
Vikentia [17]
The Newton’s law Nikolas would use to come up with this idea is the <span>Third law that states:

</span><span>When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.
</span>
So, in this case, let's name the first Body A which is the skateboard and the second body B which is <span>the compressed carbon dioxide in a fire extinguisher. Then, as shown in the figure below, according to the Third law:

</span>FA = -FB<span>

</span>

8 0
2 years ago
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In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?
IceJOKER [234]

Answer: a=1016.66 m/s^{2}

Explanation:

Acceleration a is expressed in the following formula:

a=\frac{V_{f}-V_{o}}{t}

Where:

V_{f}=610 m/s is the final velocity of the projectile

V_{o}=0 m/s  is the initial velocity of the projectile

t=0.6 s is the time

Solving:

a=\frac{610 m/s-0 m/s}{0.6 s}

a=1016.66 m/s^{2} This is the acceleration of the projectile

6 0
3 years ago
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