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aliina [53]
3 years ago
14

Describe one way in which rocks formed on Mount Moran.

Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0
Free pint because some answers it
Anarel [89]3 years ago
4 0

Answer:

One way in which the rocks are formed on Mount Moran is due to the presence of intense heat and pressure. When the slabs of sedimentary rocks got buried deep beneath the Earth's surface, they have experienced intense heat and pressure. Later on, they formed into metamorphic rocks.

Explanation:

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A sample of Cd(OH)2 is added to pure water and allowed to come to equilibrium at 25ºC. The concentration of Cd +2 = 1.7 x 10 -5M
Archy [21]

Answer:

Ksp=2.0x10^{-14}

Explanation:

Hello there!

In this case, given the solubilization of cadmium (II) hydroxide:

Cd(OH)_2(s)\rightleftharpoons Cd^{2+}(aq)+2OH^-(aq)

The solubility product can be set up as follows:

Ksp=[Cd^{2+}][OH^-]^2

Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

Ksp=(1.7x10^{-5})(3.4x10^{-5})^2\\\\Ksp=2.0x10^{-14}

Regards!

3 0
3 years ago
What can scientists learn from index fossils?
olga2289 [7]

Answer:

dating and correlating the strata in which it is found

Explanation:

3 0
3 years ago
What is the molarity of a solution containing 501mL with 35g NaCl
Vesna [10]

Answer:

Data:

mass of solute: 35g of NaCl

m.mass of solute: 58g/mol

volume of solution: 501mL

Molarity=?

Explanation:

501ml = 0.5dm3

M= g of solute/m.mass of solute*vol of solution

M= 35/58*0.5

M=1.20

6 0
3 years ago
PLEASE ANSWER NEED BY MIDNIGHT TONIGHT!!!!!!
maksim [4K]

The equation for carbon-14 emission by Radium-223 nuclei is given below:

^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of a substance with emission of radiation.

The equation for carbon-14 emission by Radium-223 nuclei is given below:

^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C

In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.

Learn more about radioactivity at: brainly.com/question/3603596

#SPJ1

5 0
1 year ago
AL(OH)3+ HCI—&gt; ALCL3 +H2O
UkoKoshka [18]

Answer:

i dont know what you're asking here. But if you're asking what it is then:

Explanation:

Aluminum Hydroxide + Hydrogen Chloride = Aluminum Chloride + Water

Al and Oh3: Aluminum Hydroxide

H and Cl: Hydrogen Chloride

Al and Cl3: Aluminum Chloride

H2O: water

btw the first letter of every element should be capitalized. While the second and theird are lowercased.

4 0
3 years ago
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