2N2 + 3O2 ---> 2NO + 2NO2
You should do it based on moles and not grams.
1.14 g O = 0.071 moles O
1 g N = 0.071 moles N
So in NO2 you need 2 moles O for each mole of N
1 g N = 0.071 moles, so you need 0.071 x 2 moles of O = 0.0.142 moles O
0.142 moles O x 16 g/mol = 2.27 grams of O. So, you are actually correct because your answer is 2.28 grams. I just prefer to work it out in moles so it makes perfect chemical sense.
Answer: The answer is S = 0.1528 cal/g °C
Explanation:
By the law of conservation of energy, energy is neither created nor destroyed.
So, energy lost by metal pieces is equal to the energy gained by water in the calorimeter.
Specific heat of water is 1 cal/g °C
⇒ heat energy Q = mSΔT, where m = mass of a substance
S = specific heat
ΔT = change in temperature
Now, the heat lost by metal piece, Q = 72×S×(96-31)
= 4680×S cal
Heat gained by water, Q = 130×1×(31-25.5)
= 715 cal
⇒ 4680×S = 715.
⇒ S = 0.1528 cal/g °C.
First consider and take note of the following:
1. When 2 or more finite amounts of substances are mix together (with different temperature) the final temperature is never equivalent to the initial temperature of any of the substances involved.
2. The substances meet at an equilibrium temperature.
3. Heat transfers from a higher temperature to a lower temperature.
Only choice (3) satisfies the conditions.
Answer: V2 = 35.54L
Explanation:
Applying
P1= 67.4, V1= 85, T1= 245, P2= 179.6, V2= ?,. T2=273
P1V1/ T1= P2V2/T2
Substitute and simplify
(67.4*85)/245 = (179.6*V2)/273
V2= 35.54L
