Can u please help me , I’m stuck it’s question e

Is iron rusting a chemical reaction? Explain why or why not.

balu736 [363]

Answer: Yes- Rusting is an oxidation reaction. The iron reacts with water and oxygen to form hydrated iron(III) oxide, which we see as rust. Iron and steel rust when they come into contact with water and oxygen – both are needed for rusting to occur. Rusting is an example of a chemical change. A chemical property describes the ability of a substance to undergo a specific chemical change. A chemical property of iron is that it is capable of combining with oxygen to form iron oxide, the chemical name of rust.

Hope this helps.... Stay safe and have a Merry Christmas!!!!!!!!!!!! :D

7 0

3 years ago

If the heat of fusion of water is 3.4 × 102 j/g, the amount of heat energy required to change 15.0 grams of ice at 0°c to 15.0 g

Shalnov [3]

If the heat of fusion of water is 3.4 × 10^2 joule/gram, the heat energy amount required to change 15.0 grams of ice at 0°c to 15.0 grams of water at 0°c is 5100 joule (5100 = 3.4 x 10^2 x 15).

The problem above can be solved by using the heat of fusion formula. The formula for calculating the heat of fusion described as C = q/m, where: C is the heat of fusion, q is the amount of heat energy required, and m is the mass of the object.

3 0

3 years ago

Which series of labels correctly identifies the indicated structures in this sketch of a cell viewed under a microscope? A.mitoc

kifflom [539]

Answer:

for the first it is B i do not know for the second

Explanation:

i took the quiz hope this helped

4 0

4 years ago

Read 2 more answers

Determine the value of the equilibrium constant, Kgoal, for the reaction

hodyreva [135]

Answer:

Part A

$K_{goal}= 3.22\times 10 ^{-66}$

Part B

$K_{goal}= 2.26\times10^{-21}$

Explanation:

Part A:

The given equation is not balanced. So, initially let's balance the equation by taking 24 moles of each of the reagent and NO.

24N₂ + 24H₂O ⇌ 24NO + 12N₂H₄

Now, simplify the equation by dividing both sides by 12. The final balanced equation is the following

2N₂ + 2H₂O ⇌ 2NO + N₂H₄

The above-balanced equation can be solved algebraically to obtain the required Kgoal value.

Adding given equations 1, 2 and 3 we obtain the required equation.

When the equations are added, the equilibrium constants of each equation are multiplied. Mathematically it can be represented as,

$K_1 \times K_2 \times K_3 = K_{goal}$

$K_{goal}= 4.10 \times 10^{-31} \times 7.40 \times 10^{-26} \times 1.06 \times 10^{-10}$

$K_{goal}= 3.22\times 10 ^{-66}$

Part B:

The required equation is balanced, Now

Let.

P₄(s)+6Cl₂(g) ⇌ 4PCl₃(g), K₁=2.00×10¹⁹ ------------------------------------ (a)

PCl₅(g) ⇌ PCl₃(g)+Cl₂(g), K₂=1.13×10⁻² --------------------------------------- (b)

By multiplying equation 2 by 4 and subtracting equation 1 from it, we get

4PCl₅(g) ⇌ P₄(s)+10Cl₂(g)

The Kgoal for the above equation is the product of four times K₂ and inverse K₁ according to the applied operation. Mathematically,

$K_{goal}= 4K_2 \times \frac{1}{K_1}$

$K_{goal}= 4(1.13\times10^{-2}) \times \frac{1}{2.00\times10^{19}}$

$K_{goal}= 2.26\times10^{-21}$

5 0

3 years ago

40 POINTS! How many moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas?

vichka [17]

Answer:

5.0 moles.

Explanation:

The balanced equation of the reaction between hydrogen and oxgen to produce water is:

It is clear that 1.0 mole of H₂ reacts with 0.5 mole of O₂ to produce 1.0 mole of H₂O.

∴ 2.5 mole of O₂ will react with 5.0 moles of H₂.

The limiting reactant is O₂ and H₂ is found in excess (1.0 mole more).

From the stichiometry: 2.5 mole of O₂ will react with 5.0 moles of H₂ to produce 5.0 moles of H₂O.

<em>∴ 5.0 moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas</em>

7 0

3 years ago