KE = (1/2)mv^2
m = 10.0 kg
v = 5.00 m/a
KE = (1/2)(10.0)(5.00)^2 = (1/2)(10.0)(25.0) = 125 J
C. 125 J
Answer:
CaCO3(s) <==> Ca2+(aq) + CO3 2-(aq)
Let X = the amount of CaCO3 dissolved in Na2CO3 or the amount of each ions formed i.e. Ca2+ and CO3 2–. Then, put this into the formula :
Ksp = [Ca2+] [CO3 2-]
5 × 10^-9 = [X]*[X]
X^2 = 5 × 10^-9
X = √5 × 10^-9
X = 7.07 x 10^-5 mole/L
So, the amount of CaCO3 dissolved in 0.1M Na2CO3 or the amount of Ca2+ and CO3 2- ions produced is 7.07 x 10^-5 mole/L
Answer:
This experiment is uncontrolled because two different masses of substance A are used.
Explanation:
A controlled experiment is a structured experiment aimed at testing a particular observation or observations. The setup of a controlled experiment helps to determine the reason why a particular observation occurs and what must have led to it.
In the experiment highlighted above, different masses of a substance were used, they were heated to different temperatures. The set up does not show any correlation between the masses of substances heated and the temperatures. It is even difficult to try to predict the hypothesis for this kind of experimental set up. All the variables in play can best be assumed to be independent of one another.
Elements of the same group show similar chemical properties as they have the same number of valence electrons. Sulfur belongs to the group 16 or 6 A or the oxygen family with 6 valence electrons. The elements of group 6 A are Oxygen, Sulfur, Selenium, Tellurium and Polonium. All of these elements show similar chemical properties. Therefore, when a biochemist studying the properties a sulfur containing biochemical compounds in the body wants to look at any other non-metal with similar properties, he has to consider other elements of the group 6 A like Oxygen (O), Selenium (Se), Tellurium (Te) and Polonium (Po).
It shifts and the temperature changes I think hope this helps
