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My name is Ann [436]
3 years ago
7

How many pennies would be in a tower that is 10 miles high?

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0
Just measure the width (or height, if you'll be stacking the pennies
a mile high) of a penny, then divide 5280 feet by whatever you find.
This is a great activity for a class, and in fact a good way to start
the project. First take one penny, and work out an answer. Then get
100 pennies, and measure them; do the same calculation to see how many
pennies it will take to make a mile. There will probably be a
difference, because you can measure 100 pennies more accurately than a
single penny. Or maybe you have a micrometer that will measure one
penny precisely. Which is better can be a good discussion starter. And
don't forget to try it in metric, too.

Just to illustrate, using a very rough estimate of a penny's width,
let's say a penny is about 3/4 inch wide. The number of pennies in a
mile will be

5280 ft 12 in 1 penny
1 mile * ------- * ----- * ------- = 5280 * 12 * 4/3 pennies
1 mi 1 ft 3/4 in

This gives about 84,480 pennies. (This method of doing calculations
with units is very helpful, and would be worth teaching.)

If we measure 100 pennies as 6 ft 1 in, we will get

5280 ft 100 pennies
1 mile * ------- * ----------- = 5280 * 100 * 12 / 73 pennies
1 mi 6 1/12 ft

This gives us 86794.5205 pennies in a mile.
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Ms. Anguiano is enjoying a bicycle ride on a country road
GalinKa [24]

Answer:

The rate is 13 miles per hour

Step-by-step explanation:

* Lets explain how to solve the problem

- Jim lives three miles east of State College

- At noon, he leaves his house and begins to walk due east at a

constant speed of 2 miles per hour

- Annie lives four miles north of State College

- At noon, she leaves her house and begins to bicycle due north at a

constant speed of 8 miles per hour

- The east is perpendicular to the north

* Lets solve the problem

∵ At noon means 12 p.m

∵ They moved till 1 p.m

∵ Jim walked for 1 hour and Annie bicycled for 1 hour

∵ The rate of Jim is 2 miles per hour

∵ The rate of Annie is 8 miles per hour

- The distance = rate × time

∴ Jim walked = 2 × 1 = 2 miles

∴ Annie bicycled = 8 × 1 = 8 miles

- Lets calculate the distance of Jim from the State College till his

position at 1 p.m

∵ Jim lives three miles east of State College

∴ His distance at 1 p.m = 3 + 2 = 5 miles east

- Lats calculate the distance of Annie from the State College till her

position at 1 p.m

∵ Annie lives four miles north of State College

∴ Her distance at 1 p.m = 4 + 8 = 12 miles North

- Lets find the distance between them at 1 p.m

∵ The north ⊥ east

- Use Pythagoras Theorem to find the distance

∴ The distance = √(5² + 12)² = √(25 + 144) = √169 = 13 miles

- The rate = distance/time

∵ The distance between them is 13 miles in 1 hour

∴ The rate = 13/1 = 13 miles per hour

* The rate is 13 miles per hour

6 0
4 years ago
A cold front hit Hartford, Connecticut. The temperature dropped by 7° F each hour from 5:00 a.m. to 9:00 a.m. What was the begin
never [62]

Hi! The temperature would be 18°.

There was a 4 hour period between 5 and 9 a.m.

So, I just took -10, and added 7 four times.

-10 + 7 + 7 + 7 + 7 = 18

Hope this helps you! Happy thanksgiving, here's a turkey!

5 0
3 years ago
The display on a calculator screen is shown below.
DerKrebs [107]

EE is a representation of "x10^)

For example,

6EE5 = 6\times10^5

So in this case,

8.49473EE8 = 8.49473\times10^8 = 849473000

4 0
3 years ago
Erica mixed 1 1/5 cups of wheat flour, 2 2/5 cups rye flour, and 2 3/5cups white flour together.
blondinia [14]
The answer would be A
7 0
3 years ago
What is the arc length of a semicircle with a radius of 11?
kap26 [50]

Answer:

The arc length of the semicircle is: 11 \pi, which is approximately 34.5575

Step-by-step explanation:

Recall that the length of a circumference of radius R is given by:

length = 2\,\pi \,R

therefore, the arc length of a semicircle (half of the circle) would be given by half of the previous expression:

length\,\,of \,\,semicircle= \pi\,R

So, in our particular case of radius 11, the formula for the arc length of the semicircle becomes:

length\,\,of \,\,semicircle= \pi\,R\\length\,\,of \,\,semicircle= 11 \pi\\length\,\,of \,\,semicircle= 34.5575

7 0
3 years ago
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