Answer: a) Yes, there is enough fance
b) 58.1° and 47.9°
c) The city will not approve, because 1/3 of the area is just 2220.5ft²
Step-by-step explanation:
a) using law of cosines: x is the side we do not know.
x² = 126² + 110² - 2.126.110.cos74°
x² = 20335.3
x = 142.6 ft
So 150 > 142.6, there is enough fance
b) using law of sine:
sin 74/ 142.6 = sinα/126 = sinβ/110
sin 74/ 142.6 = sinα/126
0.006741 = sinα/126
sinα = 0.849
α = sin⁻¹(0.849)
α = 58.1°
sin 74/ 142.6 = sinβ/110
sin 74/ 142.6 = sinβ/110
0.006741 = sinβ/110
sinβ = 0.741
β = sin⁻¹(0.741)
β = 47.9°
Checking: 74+58.1+47.9 = 180° ok
c) Using Heron A² = p(p-a)(p-b)(p-c)
p = a+b+c/2
p=126+110+142.6/2
p=189.3
A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)
A = 6661.5 ft²
1/3 A = 2220.5
So 2300 > 2220.5. The area you want to build is bigger than the area available.
The city will not approve
Answer:
C. 7/9 and 0.7 (with bar notation)
Step-by-step explanation:
The division keeps going with the remainder as 7 and 9 can only go into 70 with a 63 so to show the 7 keeps going you would have to use bar notation above 7.
Answer:
6=2r please mark brainliest
Step-by-step explanation:
Answer:
Class 4: This class of truck has a GVWR of 14,001–16,000 pounds or 6,351–7,257 kilograms. Class 5: This class of truck has a GVWR of 16,001–19,500 pounds or 7,258–8,845 kilograms.
Step-by-step explanation:
There are apparently a huge number of correct answers ...
the statement of part-a that you've attached has so few
restrictions, requirements, or specifications.
