Answer:
62, 71, 80
Step-by-step explanation:
to figure out the rule we can minus 51 and 42 which is 9. so you know the rule we can now figure out the next three rules.
The answer is 51+9, the 62+9 and so on.
There's a bunch of them like if you simplify you could get 3/4.I'll give you some more.
Examples:14/16 21/24 28/32 and 35/40.
My brain was getting tired to think...but there's more.
Hope this helps :D
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Hi!
<em>Plug in </em>
for 
<em>Multiply </em>
<em>and </em>
<em>Add </em>
<em>and </em>
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Betty's percentage is 15%.
The rate of change is the amount it changes for every missing assignment, therefore it would be -5.
Answer:
p(x) = (5x - 1) (x + 4) (x - 2)
