Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
I’m pretty sure it’s B. Toolbar
Hope this helps!! :)
The answer & explanation for this question is given in the attachment below.
False it is the Stanley cup
Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// recursive function to print digit of number in revers order
void rev_dig(int num)
{
if(num==0)
return;
else
{
cout<<num%10<<" ";
// recursive call
rev_dig(num/10);
}
}
// driver function
int main()
{
int num;
cout<<"enter a number:";
// read the number from user
cin>>num;
cout<<"digits in revers order: ";
// call the function with number parameter
rev_dig(num);
return 0;
}
Explanation:
Read the input from user and assign it to variable "num". Call the function "rev_dig" with "num" parameter.In this function it will find the last digit as num%10 and print it. Then call the function itself with "num/10". This will print the second last digit. Similarly it will print all the digits in revers order.
Output:
enter a number:1234
digits in revers order: 4 3 2 1
Diagram :