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andriy [413]
3 years ago
9

HURRY UP IF YOU ANSWER THIS QUESTION CORRECT I WILL NAME YOU BRAINLY WHAT IS 129 SQUARED

Mathematics
2 answers:
NemiM [27]3 years ago
6 0

Answer:

11.3

Step-by-step explanation:

ivanzaharov [21]3 years ago
3 0

Answer:

16641

Step-by-step explanation:

129 x 129=16641

HTH :)

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a circle is centered at (-4,9)and has a radius of 11. what is the equation of the circle. use x and y​
Sholpan [36]

Answer:

(x + 4)^2 + (y-9)^2 = 121

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k) ^2 = r^2  where (h,k) is the center and r is the radius

(x - -4)^2 + (y-9)^2 = 11 ^2

(x + 4)^2 + (y-9)^2 = 11 ^2

(x + 4)^2 + (y-9)^2 = 121

3 0
3 years ago
What's the domain of this function? I typed [-4,5] but it says it's wrong!!! Please help!!!! It's due today!
Whitepunk [10]

Answer:

negative infinity to positive infinity

Step-by-step explanation:

The graph keeps going forever on both ends.

3 0
2 years ago
Read 2 more answers
The larger leg of a right triangle is 3 cm longer than its smaller leg. The hypotenuse is 6 cm longer than the smaller leg. How
dlinn [17]
For rigt triangle with legs legnth a and b and hypotnuse legnth c

a^2+b^2=c^2

we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller

ok so

first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and

hypontuse is 6 more than shorter
c=6+b

sub 3+b for a and 6+b for c in oroiginal equation'

a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero

b-9=0
b=9

b+3=0
b=-3
fasle, legnths cannot be negative


answer is shorter side=9 cm


5 0
3 years ago
PLSS HELPP 25 POINTS AND BRAILIEST
Salsk061 [2.6K]

Answer:

\Large \boxed{\sf 136 \ m^2}

Step-by-step explanation:

Surface area of this shape = area of 2 triangles + area of 3 rectangles

(6 \times 4 \times 0.5 \times 2 )+(7 \times 5 \times 2+7 \times 6)=136

7 0
2 years ago
Find the surface area of the pyramid. the surface area of the pyramid is __in squared.
iVinArrow [24]

Answer:

561.08in^{2}

Step-by-step explanation:

S A = lw + l \sqrt{(\frac{w}{2})^{2}  + h^{2}  } + w \sqrt{(\frac{l}{2})^{2} + h^{2}  }

SA = 14(14) + 14 \sqrt{(\frac{14}{2})^{2} + 11^{2}  }+ 14 \sqrt{(\frac{14}{2})^{2} + 11^{2}  } = 561.08in^{2}

4 0
1 year ago
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