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3 years ago

HURRY UP IF YOU ANSWER THIS QUESTION CORRECT I WILL NAME YOU BRAINLY WHAT IS 129 SQUARED

Mathematics

2 answers:

NemiM [27]3 years ago

6 0

Answer:

11.3

Step-by-step explanation:

ivanzaharov [21]3 years ago

3 0

Answer:

16641

Step-by-step explanation:

129 x 129=16641

HTH :)

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3 years ago

If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

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3 years ago

Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin. Use the polygon tool to graph

Olenka [21]

The triangle is illustrated below.

<h3>How to explain the triangle?</h3>

The first thing you should find are the new vertices:

(x, y) ---> (2x, 2y) ---> (x', y')

(0, 0) ---> (2 (0), 2 (0)) ---> (0, 0)

(-4, 4) ---> (2 (-4), 2 (4)) ---> (-8, 8)

(-4, -2) ---> (2 (-4), 2 (-2)) ---> (-8, -4)

Then, you must join the ordered pairs and graph the new triangle.

See the attached graph.

Learn more about triangles on:

brainly.com/question/1058720

#SPJ1

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2 years ago

1. Triangle ABC has an angle of ABC = 60°, AB = 3 √3 cm and BC = 4 √3 cm. Determine the length of AC.

Oksi-84 [34.3K]

Answer:

see below

Step-by-step explanation:

you can use cosine law

(3 sqrt3)^2 + (4 sqrt3)^2 - 2(3 sqrt3)(4sqrt3)cos60 = AC^2

AC = sqrt39

4 0

2 years ago