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Vikentia [17]
3 years ago
7

Where would the square root of 67 be located on a number line?

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0

The closest squares greater and smaller than 67 are 64 and 81.

64<67<81

√64<√67<√81

8<√67<9

√67 is in between 8 and 9, so A is the answer.

Hope this helps!

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Step-by-step explanation:

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Ellen flipped a coin 80 times. the coin landed heads up 44 times and tails up 36 times. what is the theoretical probability of l
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2 years ago
What are the domain and range of an exponential parent function?<br><br> Help please
a_sh-v [17]

The domain and the range of an <em>exponential parent</em> function, that is, y = eˣ are equal to all <em>real</em> numbers and <em>non-negative</em> numbers, respectively. (Correct choice: C)

<h3>How to determine the domain and range of an exponential function</h3>

In this problem we should determine what an <em>exponential parent</em> function is. The most common <em>exponential</em> functions have the following form:

y = A\cdot e^{B\cdot x} + C     (1)

(1) is an <em>exponential parent</em> function for A = 1, B = 1 and C = 0.

All functions are relations with a domain and range, the domain is an <em>input</em> set related to the range, that is, an <em>output</em> set. In the case of an <em>exponential parent</em> function, the domain and the range of the expression are \mathbb{R} and y ≥ 0, respectively. (Correct choice: C)

To learn more on exponential functions: brainly.com/question/11487261

#SPJ1

8 0
1 year ago
Need help with this didn’t understand it
zaharov [31]

Answer:

Ok, the solution to the first one. See below.

Step-by-step explanation:

1>3-d\\\\\mathrm{Add\:}d\mathrm{\:to\:both\:sides}\\\\1+d>3-d+d\\\\\mathrm{Simplify:}\\\\1+d>3\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\\1+d-1>3-1\\\\\mathrm{Simplify:}\\\\d>2

See attachment below.

Best Regards!

6 0
3 years ago
If (8^9)p = 8^16 what's the value of p?
monitta

Answer:

p  = {8}^{7}

Step-by-step explanation:

(8^9)p = 8^{16 } \\  \\ p =  \frac{8^{16 } }{8^{9 } }  \\  \\  p =  {8}^{16 - 9}  \\  \\  \huge \red{ \boxed{p  = {8}^{7} }}

8 0
2 years ago
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