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Minchanka [31]
3 years ago
12

2. A gas has volume of 4.2L at 110 kPa. If temperature is constant, find the pressure of gas when the volume is change to 11.3L.

Chemistry
1 answer:
muminat3 years ago
3 0

Answer:

40.88 kPa.

Explanation:

Given that,

Volume, V₁= 4.2 L

Pressure, P₁ = 110 kPa

We need to find the pressure of the gas when the volume is changed to 11.3L at constant temperature.

According to Boyle's law, at constant temperature, volume is inversely proportional to the pressure. Mathematically,

P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{4.2\ L\times 110\ kPa}{11.3\ L}\\\\P_2=40.88\ kPa

So, the new pressure is 40.88 kPa.

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5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

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5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4}  \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Learn more: brainly.com/question/15288923

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