5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
- The molar mass of K₂C₂O₄ is 184.24 g/mol.
- The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Learn more: brainly.com/question/15288923
Answer:
(C) The average molecular speed of ethane is equal to the average molecular speed of propanol.
Explanation:
When dealing with gases, you know that the temperature and speed are related. When held at a constant temperature, the speed is also held constant. We also know that ideal gases behave the same despite their identities.
Answer : The dipole-dipole interaction.
Explanation : The kind of bond that is created by a weak electrical attraction between two polar molecules is dipole-dipole interaction.
The type of force which occurs between the positive end of one molecule and the negative end of another molecule: is dipole-dipole interaction.
For better understanding, please refer the attachment.
<span>The high-energy electron travels down an electron transport chain, losing energy as it goes.
Some of the released energy drives pumping of </span><span><span>\text H^+<span>H<span><span>+</span><span></span></span></span></span>H, start superscript, plus, end superscript</span><span> ions from the stroma into the thylakoid interior, building a gradient.
</span><span><span>H^+<span>H<span><span>+</span><span></span></span></span></span>H, start superscript, plus, end superscript</span><span> ions from the splitting of water also add to the gradient.
</span><span><span> H^+<span>H<span><span>+</span><span></span></span></span></span>H, start superscript, plus, end superscript</span><span> ions flow down their gradient and into the stroma, they pass through ATP synthase, driving ATP production in a process known as </span>chemiosmosis<span>.</span>
Answer: 1mole
Explanation:
Mole = concentration× Volume (dm3)
Mole = 2× 500/1000