A container of what volume would be required to store 60.0 moles of a gas at a pressure of 20.0 atm and a temperature of 50.0 Ce
1 answer:
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Answer:
<h2>8.13 mL</h2>Explanation:
The required volume can be found by using the formula for Boyle's law
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
From the question we have
We have the final answer as
<h3>8.13 mL</h3>Hope this helps you