Explanation:
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<em><u>Ionic bonds</u></em> <span>are the type of bonds where there is </span><u>transfer</u><span><u> </u>of electrons from one atom to another. The electrons are removed and from one atom and attached to another. A good example is salt which is composed of sodium and chlorine. Sodium readily loses one of its electrons and chlorine readily accepts it. Before losing the electron, sodium has a positive charge, but then becomes negatively charged after giving up the electron. Chlorine has a positive charge before gaining the electron but becomes negatively charged after gaining the electron. These opposite charges between sodium and chlorine attract the two elements together to form the ionic bond.</span>
Answer:
3.937 x 10⁻⁸ inches
Explanation:
Data Given:
Atomic radium in pm (picometer) = 1.00 x 10² pm
Atomic radium in inches = ?
1 pm = 10⁻¹² m
Solution:
First convert picometer to meter
As we Know
1 pm = 10⁻¹² m
then
1.00 x 10² pm = X meter
Do cross multiplication
X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm
X meter = 1 x 10⁻⁹ m
So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m
Now convert meter to inches
As
1 m = 39.37 inches
1 x 10⁻⁹ m = X inches
Do cross multiplication
X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m
X inches = 3.937 x 10⁻⁸ inches
So,
1.00 x 10² pm = 3.937 x 10⁻⁸ inches
so the radius is 3.937 x 10⁻⁸ inches
The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M
calculation
concentration = moles /volume in liters
volume in liters = 150 /1000= 0.15 L
number of moles calculation
write the equation for dissociation of Al2Cl3
that is AlCl3 ⇔ Al^3+ + 3 Cl ^-
find the moles of Cl^- formed
moles =mass/molar mass
mass in grams= 550/ 1000 =0.55 grams
molar mass of Cl^- =35.5 g/mol
moles is therefore= 0.55/35.5 =0.0155 moles
by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles
concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M
Answer:
126000J
Explanation:
From the question given, we obtained the following information:
M = 1500g
C = 4.2J/g°C
ΔT = 20°C
Q =?
Q= MCΔT
Q = 1500 x 4.2 x 20 =
Q = 126000J
