16.94 % Zn
Explanation:
First we need the molar weight of the Zn₃(PO₄)₂:
molar weight of Zn₃(PO₄)₂ = atomic weight of Zn × 3 + atomic weight of P × 2 + atomic weight of O × 4 × 2
molar weight of Zn₃(PO₄)₂ = 65.4 × 3 + 31 × 2 + 16 × 4 × 2 = 386 g/moles
Taking in account weight of 1 mole of Zn₃(PO₄)₂ we devise the following reasoning:
if 386 g of Zn₃(PO₄)₂ contains 65.4 g of Zn
then 100 g of Zn₃(PO₄)₂ contains X g of Zn
X = (100 × 65.4) / 386 = 16.94 % Zn
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