Question with four option
The Pythagorean theorem states that the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse by the formula, a² + b² = c².If a is a rational number and b is a rational number, why could c be an irrational number?
The square of rational numbers is irrational, and sum of two irrational numbers is irrational.
The product of two rational numbers is rational, and the sum of two rational numbers is irrational.
The left side of the equation will result in a rational number, which is a perfect square.
The left side of the equation will result in a rational number, which could be a non-perfect square.
Answer with Explanation
The Pythagorean theorem states that
Sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse.
⇒ a² + b² = c²
It has been asked that, a is a rational number and b is a rational number ,then why c is an Irrational number.
Suppose, a=3 ,b=4 , the set of number forming Pythagorean triplet
Then, ⇒ a² + b²
=3²+4²
= 9 +16
=25
= 5²
Here, c=5 is a Rational Number.
Now, take, a=2, b=3,the set of number not forming Pythagorean triplet
a²+b²
=2²+3²
=4 +9
=13
Now, a² + b² = c²
⇒ c²=13
But side of a triangle can't be negative.
So,Length of Hypotenuse =√13
It totally depends on which two numbers you are choosing, A set of numbers forming Pythagorean Triplet or any other set of numbers.
→ If you choose any other set of numbers which is not a Pythagorean triplet , the Hypotenuse will be an irrational number.
Option D:→ The left side of the equation will result in a rational number, which could be a non-perfect square.