Answer:
Step-by-step explanation:
Given that acceleration of an object is

is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0

So solution for distance is

First we have to rewrite this function.Instead of :^3 sqrt (...) we can write : (...)^(1/3).
f ( x ) = ( 27 x - 81 ) ^(1/3) - 5 = ( 27 * ( x - 3 ) ) ^(1/3) - 5 = = 3 * ( x - 3 )^(1/3) - 5 And this makes it easy to graph a translation.The parent function is y = x^(1/3). The zero of this function is ( 0, 0 ).
Then it will be stretched vertically by a factor of 2 and translated: 3 units right and 5 units down.
Grace weighed 167 pounds before she started her exercise program.
Step-by-step explanation:
Given,
Weight lost by Grace = 45 pounds
Weight of Grace after exercise weeks = 122 pounds
Let,
x represents the weight of Grace before she started the exercise program.
Loss means subtraction, therefore,
We will subtract the lost weight from original weight.
Original weight - Weight lost = Weight after exercise weeks

Adding 45 on both sides

Grace weighed 167 pounds before she started her exercise program.
Keywords: equation, addition
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