The correct unabbreviated electron configuration is as below
Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2
Strontium - 1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2
Carbon =1S2 2S2 2P2
<u><em> Explanation</em></u>
vanadium is in atomic number 23 in the periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2
Strontium is in atomic number 38 in periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4s2
Carbon is in atomic number 6 in periodic table therefore its electron configuration is 1s2 2s2 2p2
Answer:
the correct answer is c
Explanation:
becuase i had the same question
A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g
B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g
1mL = 1cm3
Answer:
1
Explanation:
since Na has one electron in its outer shell it has to give away that one electron in order to obtain a noble gas structure and chlorine needs to obtain one electron also to became a noble gas so it receives the electron that the sodium gave away.
Answer: (2)react completely in the reaction
limiting reactant determines the number of moles in a chemical reaction
excess reactant is the reactant with an excess number of moles
