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NNADVOKAT
[17]
2 years ago
8
Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.
Chemistry
Answer
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1
answer:
dem82
[27]
2 years ago
8
0
2C4H10 + 13O2 = 8CO2 + 10H2O
1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10
2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O
3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
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