Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.

1 answer:

8 0

2C4H10 + 13O2 = 8CO2 + 10H2O

1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10

2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O

3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O

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Water exists in liquid form between its 1. Freezing and Boiling point 2. Freezing and melting point 3. Boiling and melting point

Zigmanuir [339]

Answer:

Freezing and boiling point

Explanation:

A liquid form of any substance is an intermediate form between the solid form and the gaseous form.

Decreasing the temperature of liquid water according to the phase diagram of $H_2O$ would freeze it and we would have a phase change from liquid to solid (ice) at the freezing point of water.

Similarly, heating water to its boiling point would evaporate water and we would have a phase change from liquid to gas (water vapor).

Therefore, liquid water exists between its freezing and boiling point.

8 0

3 years ago

Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$