Answer:
At equilibrium:
[H2] = 0.005 M
[Br2] = 0.105 M
[HBr] = 0.189 M
Explanation:
H2(g) + Br2(g) ⇄ 2HBr
an "x" value will be used from reactant to produced "2x"
so at equilibrium:
[H2] = 0.1 - x
[Br2] = 0.2 - x
[HBr] = 2x
we know that Kc=[HBr]²/[H2][Br2]
Thus 62.5 = (2x)²/(0.1-x)(0.2-x)
this generate a quadratic equation: 58.5x² - 18.75x + 1.25 = 0
the x₁ = 0.23 x₂ = 0.09457
we pick 0.09457 because the two reactants can not make more than what they have. x₁ is higher than both initial reactant concentration
Then we substitute the "x₂" value at equilibrium:
[H2] = 0.1-0.09457 = 0.005 M
[Br2] = 0.2-0.09457 = 0.105 M
[HBr] = 2*0.09457 = 0.189 M
<span>It is a physical change. I goes from white, to yellow, back to white.</span>
Answer:
A balanced chemical equation must always include coefficients on every reactant and product.
Explanation:
<u>A balanced chemical equation does not need to include coefficients on every reactant and product.</u>
For example, below is a balanced chemical equation in which the reactants and the products have no coefficients whatsoever:
NaOH(aq) + HCl (aq) -----> NaCl (s) + H2O (l)
<em>Of course, a properly written chemical equation must include the states of matter of all the substances in the reaction and the number of atoms of each element must balance both in the reactant and product sides of the equation. Generally, a balanced chemical equation must obey the law of conservation of matter which opines that matter can neither be created nor destroyed but can only be converted from one form to another. </em>
Hence, that a balanced chemical equation must always include coefficients on every reactant and product is not true.
Answer is 67.8%
To find the percent yield the equation is actual yield over theoretical yield, and multiply by 100. In this problem it is 4.06996 / 6 = 0.678 x 100 = 67.8%
The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles
<u>Given data :</u>
Moles of strontium nitrate = 6.15 moles
<h3>Ionization of Strontium Nitrate </h3>
When strontium nitrate ( 
) is placed in water it will dissociates into its ions because strontium nitrate is an ionic compound.
Next step : Represent the ionization of strontium nitrate
From the Stoichiometry of the chemical reaction
I mole of strontium nitrate = 2 moles of Nitrate ions
6.15 mole of strontium nitrate = 2 * 6.15
= 12.3 moles of Nitrate
Hence we can conclude that The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles.
Learn more about Stoichiometry of chemical reaction : brainly.com/question/27058367
