All categories

4 years ago

If 5.12 liters of a 2.75 M phosphoric acid is neutralized by magnesium hydroxide solution of 4.00 M.

Chemistry

2 answers:

Tresset [83]4 years ago

8 0

Answer:

5.28 L

Explanation:

Step 1:

Data obtained from the question.

Volume of acid (Va) = 5.12L

Molarity of acid (Ma) = 2.75M

Molarity of base (Mb) = 4M

Volume of base (Vb) =.?

Step 2:

The balanced equation for the reaction

2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O

From the balanced equation above,

Mole ratio of the acid (nA) = 2

Mole ratio of the base (nB) = 3

Step 3:

Determination of the volume of the base.

This is illustrated below:

MaVa/MbVb = nA/nB

2.75 x 5.12 / 4 x Vb = 2/3

Cross multiply

4 x 2 x Vb = 2.75 x 5.12 x 3

Divide both side by 4 x 2

Vb = (2.75 x 5.12 x 3)/(4 x 2)

Vb = 5.28 L

Therefore, the volume of the base is 5.28 L

worty [1.4K]4 years ago

6 0

Answer:

The volume of the base Mg(OH)2 used is 5.28 L

Explanation:

Step 1: Data given

Volume of phosphoric acid = 5.12 L

Concentration of phosphoric acid = 2.75 M

concentration of magnesium hydroxide = 4.00 M

Step 2: The balanced equation

2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O

Step 3: Calculate the volume of magnesium hydroxide needed

a*Cb*Vb = b*Ca*Va

⇒with a = the coefficient of H3PO4 = 2

⇒with Cb = the concentration of Mg(OH)2 = 4.00 M

⇒with Vb = the volume of Mg(OH)2 = TO BE DETERMINED

⇒with b = the coefficient of Mg(OH)2 = 3

⇒with Ca = the concentration of H3PO4 = 2.75 M

⇒with Va = the volume of H3PO4 = 5.12 L

2 * 4.00 * Vb = 3 * 2.75 * 5.12

Vb = (3*2.75 * 5.12) / (2*4.00)

Vb = 5.28 L

The volume of the base Mg(OH)2 used is 5.28 L

You might be interested in

An electron in a hydrogen atom moves from level 1 to level 4. The electron then drops from level 4 to level 2. Which

masya89 [10]

Answer:

Your answer would be B because In the first move energy was absorbed, because when energy is gained an electron moves to a higher energy level in the second move energy will be released because that is how an atom moves to a lower energy level. The jump from level 1 to 4 was bigger than the drop from 4 to 2, because in the first move it moved from more orbitals. thus describing the the energy in the first move had a far energy released in the second move.

4 0

3 years ago

What's the empirical formula of a molecule containing 18.7% element A, 16.3%

Makovka662 [10]

C I think it is c I think hope it issue

8 0

3 years ago

10. 17.5 g of NaOH were dissolved in 350 mL of water. The solution was titrated with HNO3 to a methyl orange endpoint (methyl or

Tomtit [17]

1747.2 ml of HNO3 is required to reach methyl orange endpoint.

Explanation:

Number of moles of NaOH solution having 17.5 gram NaOH in 350ml of water.

Atomic weight of NaOH = 40 g/mol

thus number of moles= 17.5/40

= 0.437 moles

Now the molarity of the solution is calculated as

M=n/C

= 0.437/O.35 LITRES

= 1.248 M solution of the base

the molarity of acid is given as 0.25 M of HNO3

From the formula

M1V1=M2V2 we can calculate the volume of HNO3 required to make solution acidic.

1.248*350= 0.25*v2

v2= 1.248*350/0.25

= 1747.2 ml

Thus 1747.2 ml of HNO3 is required.

3 0

3 years ago

How long does it take light from the nearest star other than the Sun to reach Earth? A) Less than 1 second B) About 1 hour C) Ab

andrew-mc [135]

Your answer should be D. About 4 years. Hope this helps! =^-^=

<em>(The light reflected from the surface of the Moon takes only a second to reach Earth. The Sun is more than 8 light-minutes away. And so, if the light from the nearest star (Alpha Centauri) takes more than 4 years to reach us, we're seeing that star 4 years in the past.) Quora.com</em>

5 0

3 years ago

If all of the energy from burning 281.0 g of propane (ΔHcomb,C3H8 = –2220 kJ/mol) is used to heat water, how many liters of wate

lapo4ka [179]

This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.

<h3>Combustion:</h3>

In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

Hence, we can calculate the heat released from this reaction by using the mass, which has to be converted to moles, and the given enthalpy of combustion:

$Q=281.0g*\frac{1mol}{44.09g}*-2220\frac{kJ}{mol}*\frac{1000J}{1kJ}\\ \\ Q=-1.415x10^7 J$

<h3>Calorimetry:</h3>

In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

$Q=mC\Delta T$

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

$m=\frac{Q}{C\Delta T} =\frac{1.415x10^7J}{4.184\frac{J}{g\°C}(100.0\°C-20.0\°C)}\\ \\m=4.227x10^4g$

Finally, we convert it to liters as required:

$V=4.227 x10^4g*\frac{1mL}{1.00g}*\frac{1L}{1000mL} \\\\V=42.27L$

Learn more about calorimetry: brainly.com/question/1407669

4 0

2 years ago