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4 years ago

How do similar (S-S or N-N) magnetic poles interact?

2 answers:

7 0

Magnets with the same polarity (N-N or S-S) repel one another along the same direction. This agrees to the common rule that like poles repel and unlike poles attract. Hope this answers the question. Have a nice day. Feel free to ask more questions.

ryzh [129]4 years ago

5 0

Explanation:

Magnet has two poles: (1) North pole and (2) South pole.

Like poles repel each other. If the like poles are interacting each other then there will be force of repulsion in between these poles.

Unlike poles attract each other. If the unlike poles are interacting each other then there will be force of attraction in between these poles.

S-S and N-N magnetic poles repel each other.

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Answer: At that moment, all the baseball's kinetic energy has been converted to potential energy.

Explanation: I took the test

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2 years ago

3. Luckily, you defeated the trolll Now you have to defeat a three eyed raven to defeat the raven, you must roll the sided

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3 years ago

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Think about the sound waves and light waves that are transmitted when you use a computer, watch TV, or use your phone. How are t

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Answer:

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3 years ago

*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude

kvv77 [185]

Answer:

Approximately $3.86\; {\rm N}$ (given that the magnitude of this charge is $-7.35\; {\rm \mu C}$ .)

Explanation:

If a charge of magnitude $q$ is placed in an electric field of magnitude $E$ , the magnitude of the electrostatic force on that charge would be $F = E\, q$ .

The magnitude of this charge is $q = 7.35\; {\rm \mu C}$ . Apply the unit conversion $1\; {\rm \mu C} = 10^{-6}\; {\rm C}$ :

$\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}$ .

An electric field of magnitude $E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}}$ would exert on this charge a force with a magnitude of:

$\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}$ .

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

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2 years ago

An electron has a charge of - 1.6x10 ^ - 19 C and a proton has a charge of 1.6x 10 ^ - 19 C . In a hydrogen atom, the distance b

ra1l [238]

Answer:, , 8.2 . 10^-6, ATTRACTIVE

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law

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3 years ago