Answer:
1.503 J
Explanation:
Work done in stretching a spring = 1/2ke²
W = 1/2ke²........................... Equation 1
Where W = work done, k = spring constant, e = extension.
Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.
Substitute into equation 1
W = 1/2(26)(0.34²)
W = 13(0.1156)
W = 1.503 J.
Hence the work done to stretch it an additional 0.12 m = 1.503 J
Option A is correct answer
Answer:
10.88 km
Explanation:
We shall represent displacement in terms of i , j unit vectors in the direction of east and north .
4.5 km due west
D₁ = - 4.5 i
6.7 km at an angle of 27° south of west
D₂ = - 6.7 cos27 i - 6.7 sin27j
= - 6.7 x .89 i - 6.7 x .45 j
= - 5.96i - 3 j
Total displacement
= D₁ + D₂
= - 4.5 i - 5.96i - 3 j
= -10.46 i - 3j
Magnitude = √ ( 10.46² + 3²)
= √ ( 109.41 + 9)
= √ 118.41
= 10.88 km .
Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:

where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have

And so

And using

, we find K2: