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Rama09 [41]
3 years ago
11

Which option in presentation software can you use to apply a “fly in” effect to the objects on a slide? A)flowchart B)shapes C)

animation D) slide transition
Computers and Technology
2 answers:
galben [10]3 years ago
7 0
It is animation because you can't use it on a flowchart and slide transition and shapes is a 50/50 answer and animation is more definite  <span />
LUCKY_DIMON [66]3 years ago
6 0

The answer is Animation.  

In PowerPoint, If you want to make a piece of text or an object have a “Fly in” entrance effect, then the Animation option or Tab is where you would be required to click. Once this option is selected, a list of animation style will pop up. Continue to click on the “Fly in” animation style. This effect makes the objects fly in from the bottom, top, right, or left.


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How do i get around goguardian from a chromebook
Dafna11 [192]

Answer:

Navigate to your GoGuardian Classroom.

Click the Students tab.

Click the X icon to the right of the student's name.

Confirm by selecting Remove Student from the popup.

Explanation:

GoGuardian Off-campus filtering. Even after class, students still need access to the best learning tools for their education. ... Using Google's Admin Console and Chrome OS, GoGuardian is able to offer its complete Chromebook filtering and monitoring software wherever the device may be.

3 0
3 years ago
How many years does it take in total to complete Bachelor’s, Master’s, and Phd in CS?
muminat

Answer:

3 years of study - Bachelor's degree

2 years of research - Master's degree

3 years of research to earn a PhD

So, On total it would take 8 years!

7 0
3 years ago
CODING TIME
Fynjy0 [20]

Answer:

food_list = ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

one_more = ['meat']

extend_list = food_list + one_more

print(extend_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'meat']

food_list.append('milk')

print(food_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'milk']

food_list.insert(0, 'cake')

print(food_list)

Output : ['cake', 'rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

flowers = ['rose', 'hibiscus', 'lily']

flowers.remove('rose')

print(flowers)

Output : ['hibiscus', 'lily']

To remove rose using pop()

flowers.pop(0)

Explanation:

The + operator and append method adds elements to the end of an existing list item.

The insert method adds element at the specified index

Remove method deletes element by stating the name of the element to be deleted while pop deletes element using the index value of the element.

7 0
2 years ago
When it's time to change career paths, it's a good idea to first​
yarga [219]

Answer:

Go for an interview before quitting your job.

Explanation:

You don't want to lose your job, do you? :)

8 0
3 years ago
Read 2 more answers
Half of the integers stored in the array data are positive, and half are negative. Determine the
jonny [76]

Answer:

Check the explanation

Explanation:

Below is the approx assembly code for above `for loop` :-

1). mov ecx, 0

2). loop_start :

3).    cmp ecx, ARRAY_LENGTH

4).    jge loop_end

5).    mv temp_a, array[ecx]

6).    cmp temp_a, 0

7).    branch on nge

8).        mv array[ecx], temp_a*2

9).   add ecx, 1

10).   jmp loop_start

11). loop_end :

Assumptions :-

*ARRAY_LENGTH is register with value 1000000

*temp_a is a register

Frequency of statements :-

1) will be executed one time

3) will be executed 1000000 times

4) will be executed 1000000 times

5) will be executed 1000000 times

6) will be executed 1000000 times

7) `nge` will be executed 1000000 times, branch will be executed 500000 times

8) will be executed 500000 times

9) will be executed 1000000 times

10) will be executed 1000000 times

Cost of statements :-

1) 10 ns

3) 10ns + 10ns + 10ns [for two register accesses and one cmp]

4) 10ns [for jge ]

5) 10ns + 100ns + 10ns [10ns for register access `ecx`, 100ns for memory access `array[ecx]`, 10ns for mv]

6) 10ns + 10ns [10ns for register_access `temp_a`, 10ns for mv]

7) 10ns for nge, 10ns for branch

8) 30ns + 110ns + 10ns

10ns + 10ns + 10ns for temp_a*2 [10ns for moving 2 into a register, 10ns for multiplication],

110ns for array[ecx],

10ns for mv

9) 10ns for add, 10ns for `ecx` register access

10) 10ns for jmp

Total time taken = sum of (frequency x cost) of all the statements

1) 10*1

3) 30 * 1000000

4) 10 * 1000000

5) 120 * 1000000

6) 20 * 1000000

7) (10 * 500000) + (10 * 1000000)

8) 150 * 500000

9) 20 * 1000000

10) 10 * 1000000

Sum up all the above costs, you will get the answer.

It will equate to 0.175 seconds

7 0
3 years ago
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