Complete Question:
The mass of the sphere is 0.151 kg. What is the rotational inertia of the wheel? Recall that the radius of the sphere is about 0.312 m. Express your answer with three significant figures in Kg.m².
Answer:
I = 5.88*10⁻³ kg.m²
Explanation:
It can be showed that the rotational inertia (or moment of inertia) for a solid sphere of radius r and mass m, regarding any axis passing through the center of the sphere, can be expressed as follows:
I = (2/5)*m*r² (1)
where m= 0.151 kg, and r =0.312 m. (Our givens).
Replacing in (1) we have:
I = (2/5)*0.151 kg*(0.312m)² = 5.88*10⁻³ kg.m²
Every organism may classified into seven level of classifications, such that each level contains organisms with similar characteristics. Kingdom is the largest and the broadest level of classification while species is the smallest and most specific level of classification. Therefore from the largest to the smallest the order is as follows:
Kingdom
Phylum
Class
Order
Family
Genus
Species
Answer:
Explanation:
This question pertains to resonance in air column. It is the case of closed air column in which fundamental note is formed at a length which is as follows
l = λ / 4 where l is length of tube and λ is wave length.
here l = .26 m
λ = .26 x 4 = 1.04 m
frequency of sound = 330 Hz
velocity of sound = frequency x wave length
= 330 x 1.04
= 343.2 m /s
b )
Next overtone will be produced at 3 times the length
so next length of air column = 3 x 26
= 78 cm
c )
If frequency of sound = 256 Hz
wavelength = velocity / frequency
= 343.2 / 256
= 1.34 m
= 134 cm
length of air column for resonance
= wavelength / 4
134/4
= 33.5 cm
I believe the answer is alternative circuit
