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3 years ago

Average velocity equals distance travel divided by

Physics

2 answers:

harina [27]3 years ago

7 0

"<u>Displacement</u>" is the distance and direction between the start point and the end point

<em>Average velocity = (displacement) / (time for the trip)</em>

babymother [125]3 years ago

3 0

Average velocity =TOTAL Distance Traveled /TOTAL time taken

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Why do many species that existed 35 million years ago no longer exist

GenaCL600 [577]

Answer:

There are several reasons for the extinction of species. Some of these can include climate change, natural disasters, environmental destruction, or over-hunting. All of these factors can contribute to the deaths of various animals which ultimately leads to extinction if left unchecked.

Explanation:

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3 years ago

Four of the wavelengths of the Balmer series occur in the visible spectrum (656 nm, 486 nm, 434 nm, and 410 nm). In which region

djyliett [7]

Answer: radio waves, microwaves, infrared waves.

Explanation:

Electromagnetic spectrum increases in wavelength and decreases with frequency in the following order

Gamma ray, X ray, Ultraviolet rays, Visible light, Infrared rays, Radio waves.

Since 397nm is greater than the value of visible spectrum, this shows that radio waves, microwaves and infrared wave falls in the spectrums of the wavelength value.

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3 years ago

What is the friction

Mnenie [13.5K]

Explanation:

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3 years ago

Explain an example of how energy is transferred from one form to another

scoray [572]

Answer:

read the explanation

Explanation:

Purchased electricity is fed into our TVs and is converted to light and sound.

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Chemical Energy is converted to Electrical Energy (stove)

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3 years ago

The mass of the Sun is 2 × 1030 kg, and the distance between Neptune and the Sun is 30 AU. What is the orbital period of Neptune

Veronika [31]

Kepler's third law states that, for a planet orbiting around the Sun, the ratio between the cube of the radius of the orbit and the square of the orbital period is a constant:
$\frac{r^3}{T^2}= \frac{GM}{4 \pi^2}$ (1)
where
r is the radius of the orbit
T is the period
G is the gravitational constant
M is the mass of the Sun

Let's convert the radius of the orbit (the distance between the Sun and Neptune) from AU to meters. We know that 1 AU corresponds to 150 million km, so
$1 AU = 1.5 \cdot 10^{11} m$
so the radius of the orbit is
$r=30 AU = 30 \cdot 1.5 \cdot 10^{11} m=4.5 \cdot 10^{12} m$

And if we re-arrange the equation (1), we can find the orbital period of Neptune:
$T=\sqrt{ \frac{4 \pi^2}{GM} r^3} = \sqrt{ \frac{4 \pi^2}{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} )(2\cdot 10^{30} kg)}(4.5 \cdot 10^{12} m)^3 }= 5.2 \cdot 10^9 s$

We can convert this value into years, to have a more meaningful number. To do that we must divide by 60 (number of seconds in 1 minute) by 60 (number of minutes in 1 hour) by 24 (number of hours in 1 day) by 365 (number of days in 1 year), and we get
$T=5.2 \cdot 10^9 s /(60 \cdot 60 \cdot 24 \cdot 365)=165 years$

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3 years ago