Answer:
Length of segment QV = 35 units
Step-by-step explanation:
As shown in the figure attached,
Diagonals of TQVS are perpendicular to each other. Therefore TQVS will be a kite. By the property of a kite,
"There are two pairs of the sides which are equal in measure."
Therefore, TS ≅ TQ and SV ≅QV
Since TS ≅ TQ,
3x + 2 = 29 [Given: TQ = 29 units]
3x = 29 - 2
3x = 27
x = 9
Another pair of the consecutive sides is,
SV ≅ QV ≅ (4x - 1)
By substituting the value of x,
QV = (4 × 9) - 1
= 36 - 1
= 35 units
Therefore, length of segment QV = 35 units
The answer is A in my opinion
Answer:
60 units
Step-by-step explanation:
use the distance formula
AB= 20
BC = 15
AC = 25
perimeter = 60
y=-5x-44
Step-by-step explanation:
5x+y=13 passes through (15,31)
rearrange the equation to y=mx+c
5x+y=13
y=-5x+13
substitute the points (15,31)
y=5x+c
31=5(15)+c
31=75+c
-44=c
y=-5x-44
Can be written as 5x+y=-44
