Answer: Option (b) is the correct answer.
Explanation:
Buffere is defined as the solution to whom when an acid or base is added then it resists any in change in pH of the solution.
This is because a buffer has the ability to not get affected by the addition of small amounts of an acid or a base. So, basically it keeps the concentration of both hydrogen ions and hydroxides equal. As a result, it helps in maintaining the pH of the solution.
And, the capacity of a buffer solution to resist the change is known as buffer capacity.
Thus, we can conclude that buffering capacity refers to the extent to which a buffer solution can counteract the effect of added acid or base.
Answer: avogadros number/constant
Explanation:
<span>An iron fence is left on painted and it reacts with the oxygen in the air form forming rust. the formation of the rest is an oxidation-reduction reaction but it is also an example of a double-displacement reaction.
</span><span>cooking requires continuous addition of energy to the chemical reactions the are taking place the chemical reaction involved in cooking can be described as a chemical change.
</span><span>measuring how quickly a reactanat disappears in one way to measure the rate of the reaction</span>
Answer : The volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.
Explanation :
Let the volume of sodium benzoate (salt) be, x
So, the volume of benzoic acid (acid) will be, (100 - x)
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:

x = 29.0
The volume of sodium benzoate = x = 29.0 mL
The volume of benzoic acid (acid) = (100 - x) = (100 - 29.0) = 71 mL
Thus, the volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.
Answer:
yes
Explanation:
the results are CO2 and H2O, which usually appear after some kind of combustion.(combustion=burning)
hope this helps!