Answer:
C
Explanation:
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The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
Learn more about molarity:
brainly.com/question/15370276
Answer: 1.05
Explanation:
On ionization, hydrobromic acid completely dissociates into hydrogen ion and bromine ion. The equation is stated below
HBr <--> H+ + Br-
Recall that pH = - log(H+)
Concentration of hydrogen ion (H+) = 0.09M
So, pH = - log (0.09)
pH = - (-1.05)
pH = 1.05
The pH of 0.09M solution of HBr is 1.05. Thus, it is highly acidic.
